Problem 54
Question
Explain why, if \(f(b) \geq 0\) and \(f\) is decreasing on \([a, b],\) that the left endpoint estimate is an upper bound for the area below the graph of \(f\) on \([a, b]\)
Step-by-Step Solution
Verified Answer
The left endpoint estimate is an upper bound because the function \( f \) is decreasing, making \( f(a) \) the greatest height over \([a, b]\).
1Step 1: Understanding the Function's Behavior
We are given a function \( f \) that is decreasing on the interval \([a, b]\) and that \( f(b) \geq 0 \). This means as we move from \( a \) to \( b \), the function values become smaller or remain constant.
2Step 2: Recalling Left Endpoint Approximation Method
The left endpoint approximation method estimates the area under a curve using rectangle heights determined by the function's value at the left endpoint of each subinterval. So for one big rectangle on \([a, b]\), the height would be \(f(a)\) and base would be \(b-a\).
3Step 3: Analyzing the Sign of the Function
Since the function \( f \) is decreasing and \( f(b) \geq 0 \), we know \( f(a) \geq f(x)\) for any \( x \) between \( a \) and \( b \). Thus, the value \( f(a) \) is greater than or equal to the function's value at any other point in this interval.
4Step 4: Calculating the Left Endpoint Estimate
The area of the rectangle using the left endpoint method would be \( f(a) \times (b-a) \). This represents an overestimate, as \( f(a) \) is larger than the actual values of \( f \) at all points in the interval \([a, b]\).
5Step 5: Conclusion on Estimation being an Upper Bound
Because \( f(a) \geq f(x) \) for all \( x \) in \([a, b]\) and the rectangle height is consistently at \( f(a) \), the total rectangle area overestimates the true area under the curve, making it an upper bound.
Key Concepts
Left Endpoint ApproximationUpper Bound EstimationArea Under the Curve
Left Endpoint Approximation
When trying to estimate the area under a curve, one can use various approximation methods. The left endpoint approximation is one of these methods. It assumes that the function's height remains constant across the interval, taken from the leftmost point. Breaking it down:
- You choose a certain number of subintervals within the overall interval \( [a, b] \).
- For each subinterval, the height of the rectangle is determined by the value of the function at the left endpoint.
- The base of each rectangle is simply the width of the subinterval.
Upper Bound Estimation
An upper bound estimate is a value that is greater than or equal to the quantity being estimated. In the context of approximating the area under a curve, employing the left endpoint approximation can give an upper bound estimate.
- This happens because, with a decreasing function, the left endpoint method always picks the largest function value within any subinterval.
- As a result, when the curve is below its left endpoint height, all areas created are overestimates.
Area Under the Curve
Finding the area under a curve is an important application in calculus. This area represents the integral of the function over a specified interval. When dealing with a function that decreases across an interval, the task is about determining the region between the curve and the x-axis.
- The function value changes, causing different portions of the graph to cover different areas.
- Methods like left endpoint approximation help in estimating this area when exact calculation is difficult.
Other exercises in this chapter
Problem 52
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