Problem 54
Question
Evaluate. $$ \int_{0}^{b} k e^{-k x} d x $$
Step-by-Step Solution
Verified Answer
The integral evaluates to \( 1 - e^{-kb} \).
1Step 1: Understand the Integral
We are given the integral \( \int_{0}^{b} k e^{-kx} \, dx \), where \( k \) is a constant and \( b \) is the upper limit of integration. This is an exponential integral that typically involves substitution for simplification.
2Step 2: Choose a Substitution
Let \( u = -kx \). Then, differentiate to find \( du = -k \, dx \), or equivalently, \( dx = -\frac{1}{k} \, du \). Substitute these into the integral.
3Step 3: Change the Limits of Integration
When \( x = 0 \), \( u = -k \times 0 = 0 \). When \( x = b \), \( u = -kb \). Thus, the new limits of integration are from \( 0 \) to \( -kb \).
4Step 4: Substitute and Simplify the Integral
Substitute \( u = -kx \) and \( dx = -\frac{1}{k} \, du \) into the integral:\[\int_{0}^{-kb} k e^{-kx} \, dx = \int_{0}^{-kb} e^{u} \left(-\frac{1}{k}\right) \, du = -\int_{0}^{-kb} e^{u} \, du.\]
5Step 5: Evaluate the Integral
The integral \(-\int_{0}^{-kb} e^{u} \, du\) can be evaluated as:\[= -[e^{u}]_{0}^{-kb} = -(e^{-kb} - e^{0}) = -(e^{-kb} - 1).\]
6Step 6: Simplify and Finalize
The final expression simplifies to:\[1 - e^{-kb}.\]Thus, the evaluated integral is \( 1 - e^{-kb} \).
Key Concepts
Exponential IntegralIntegration by SubstitutionCalculus Problem Solving
Exponential Integral
An exponential integral involves the integration of an expression containing an exponential function, typically of the form \( e^{ax} \) where \( a \) is a constant. These types of integrals appear frequently in calculus, especially when dealing with natural processes or decay problems that can be modeled by exponential functions. Understanding exponential integrals is essential for solving problems that involve continuous growth or decay. In our exercise, we had the function \( k e^{-kx} \), where \( k \) is a constant and \( e^{-kx} \) represents an exponential decay:
- The presence of the negative sign in the exponent indicates that the function decays as \( x \) increases.
- These integrals often require specific techniques, such as integration by substitution, to simplify the computation.
Integration by Substitution
Integration by substitution is a fundamental technique used to simplify complex integrals. It is analogous to the reverse process of the chain rule in differentiation. The main idea is to substitute a part of the integral with a new variable, making the integral easier to evaluate. Here's how it works:
- Identify a component of the integral that, when replaced by a new variable, simplifies the integrand.
- In our exercise, we chose \( u = -kx \). This substitution helps because it simplifies the exponential function into \( e^{u} \).
- Once the substitution is made, differentiate to find \( du \), and express \( dx \) in terms of \( du \).
- Don't forget to change the limits of integration to match the new variable, as we did when converting \( x \) limits to \( u \) limits: from \( 0 \) to \(-kb\).
Calculus Problem Solving
Calculus problem solving involves applying various techniques and methods to evaluate integrals, differentiate functions, or solve mathematical models. When faced with an integral like \( \int_{0}^{b} k e^{-kx} \, dx \), a structured approach is essential for successful problem solving:
- Start by analyzing the integral to understand its components and potential difficulties.
- Determine the most suitable integration technique. In this case, integration by substitution was used to handle the exponential function effectively.
- Change variables if needed, adjust integration limits appropriately, and carry out the substitution.
- After substitution, simplify the integral to find a more tractable form, such as \( \int_{0}^{-kb} e^{u} \, du \).
- Finally, calculate the antiderivative and return to the original variables if required, ensuring the solution is expressed in terms of the given limits and terms.
Other exercises in this chapter
Problem 53
Find f such that: $$ f^{\prime}(x)=3 x^{2}-5 x+1, \quad f(1)=\frac{7}{2} $$
View solution Problem 53
Evaluate. $$ \int_{a}^{b} e^{2 t} d t $$
View solution Problem 54
Evaluate. $$ \int x^{n} \ln x d x, \quad n \neq-1 $$
View solution Problem 54
Average population. The population of the United States can be approximated by $$ P(t)=282.3 e^{0.01 t} $$ where \(P(t)\) is in millions and \(t\) is the number
View solution