Problem 54
Question
Establish the following properties of integrable vector functions. a. The Constant Scalar Multiple Rule: $$ \int_{a}^{b} k \mathbf{r}(t) d t=k \int_{a}^{b} \mathbf{r}(t) d t \quad \text { (any scalar } k ) $$ The Rule for Negatives, $$ \int_{a}^{b}(-\mathbf{r}(t)) d t=-\int_{a}^{b} \mathbf{r}(t) d t $$ \(\quad\) is obtained by taking \(k=-1\) b. The Sum and Difference Rules: $$ \int_{a}^{b}\left(\mathbf{r}_{1}(t) \pm \mathbf{r}_{2}(t)\right) d t=\int_{a}^{b} \mathbf{r}_{1}(t) d t \pm \int_{a}^{b} \mathbf{r}_{2}(t) d t $$ c. The Constant Vector Multiple Rules: $$ \begin{array}{l}{\int_{a}^{b} \mathbf{C} \cdot \mathbf{r}(t) d t=\mathbf{C} \cdot \int_{a}^{b} \mathbf{r}(t) d t \quad \text { (any constant vector } \mathbf{C} )} \\ {\text { and }} \\ {\int_{a}^{b} \mathbf{C} \times \mathbf{r}(t) d t=\mathbf{C} \times \int_{a}^{b} \mathbf{r}(t) d t \quad \text { (any constant vector } \mathbf{C} )}\end{array} $$
Step-by-Step Solution
VerifiedKey Concepts
Constant Scalar Multiple Rule
An important application of this rule is the Rule for Negatives, which is just a specific case where \( k = -1 \). This results in the following property: \[\int_{a}^{b} (-\mathbf{r}(t)) \, dt = -\int_{a}^{b} \mathbf{r}(t) \, dt\] This rule tells us that the integral of the negative of a vector function is simply the negative of the integral of that function.
Sum and Difference Rules
This aspect becomes particularly advantageous when dealing with intricate functions in applications of physics and engineering, where each vector might represent a different dimension or physical quantity.
Constant Vector Multiple Rules
- For the dot product, the rule states: \[\int_{a}^{b} \mathbf{C} \cdot \mathbf{r}(t) \, dt = \mathbf{C} \cdot \int_{a}^{b} \mathbf{r}(t) \, dt\]
- For the cross product, it states: \[\int_{a}^{b} \mathbf{C} \times \mathbf{r}(t) \, dt = \mathbf{C} \times \int_{a}^{b} \mathbf{r}(t) \, dt\]
If you’re performing these types of integrations, the rules reveal that you can compute the integral of the vector function first, and then perform the dot or cross product with the constant vector. This approach is efficient as it reduces the complexity of calculations, especially when vector operations are involved in the analysis of forces, fields, and other vector quantities in engineering and physics.