Problem 54
Question
Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. If \(A\) and \(B\) are mutually exclusive and \(P(B) \neq 0\), then \(P(A \mid B)=0\)
Step-by-Step Solution
Verified Answer
The statement is true. Since events A and B are mutually exclusive, they cannot both occur at the same time, meaning P(A ∩ B) = 0. Using the conditional probability formula, \(P(A \mid B)=\frac{P(A\cap B)}{P(B)}=\frac{0}{P(B)}\). As P(B) ≠ 0, \(P(A \mid B) = \frac{0}{P(B)} = 0\).
1Step 1: Conditional Probability Formula
Recall the formula for conditional probability: \(P(A \mid B)=\frac{P(A\cap B)}{P(B)}\).
2Step 2: Mutually Exclusive Events
Events A and B are mutually exclusive, which means they cannot both occur at the same time. In other words, their intersection is empty, so P(A ∩ B) = 0.
3Step 3: Substitute into the Formula
Substitute P(A ∩ B) = 0 into the conditional probability formula: \(P(A \mid B)=\frac{P(A\cap B)}{P(B)}=\frac{0}{P(B)}\).
4Step 4: Final Result
Since P(B) ≠ 0 and 0 divided by any nonzero number is 0, we have \(P(A \mid B) = \frac{0}{P(B)} = 0\).
Thus, the statement is true: If A and B are mutually exclusive and P(B) ≠ 0, then P(A | B) = 0.
Key Concepts
Mutually Exclusive EventsConditional ProbabilityIntersection of Events
Mutually Exclusive Events
In probability theory, mutually exclusive events are events that cannot happen at the same time. Imagine flipping a coin – it can land either on heads or tails, but not both. This is a classic example of mutually exclusive events. If you have two events, say A and B, and they are mutually exclusive, then the occurrence of one prevents the other from happening.
Because they don’t overlap, their intersection is empty. Mathematically, if A and B are mutually exclusive, we write this as follows:
Because they don’t overlap, their intersection is empty. Mathematically, if A and B are mutually exclusive, we write this as follows:
- The intersection: \( P(A \cap B) = 0 \)
Conditional Probability
Conditional probability is the probability of an event occurring given that another event has already occurred. It’s like figuring out the chances of a rainy day given that you've already seen clouds forming in the sky. For two events A and B, the conditional probability of A given B is represented by \( P(A \mid B) \).
We use the formula:
We use the formula:
- \( P(A \mid B) = \frac{P(A \cap B)}{P(B)} \)
Intersection of Events
The intersection of events in probability refers to the scenario where two or more events occur simultaneously. For events A and B, their intersection, written as \( A \cap B \), represents outcomes that are common to both events.
In practical terms, imagine you’re in a situation where you want both a sunny day and no homework to do. The intersection here is that specific set of conditions where both happen at the same time. In mathematical expressions, if the events are mutually exclusive (as discussed earlier), then their intersection is the empty set:
In practical terms, imagine you’re in a situation where you want both a sunny day and no homework to do. The intersection here is that specific set of conditions where both happen at the same time. In mathematical expressions, if the events are mutually exclusive (as discussed earlier), then their intersection is the empty set:
- \( P(A \cap B) = 0 \)
Other exercises in this chapter
Problem 52
Suppose that \(A\) and \(B\) are mutually exclusive events and that \(P(A \cup B) \neq 0 .\) What is \(P(A \mid A \cup B)\) ?
View solution Problem 53
Let \(E\) and \(F\) be independent events; show that \(E\) and \(F^{c}\) are independent.
View solution Problem 55
Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, explain why or give an example to show why it is false.
View solution Problem 56
Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. If \(A\) and \
View solution