Problem 54
Question
Determine a value of \(k\) for which the graph of the given Cartesian equation is a point. \(x^{2}+y^{2}-16 x+k=0\)
Step-by-Step Solution
Verified Answer
The value of \(k\) for which the graph is a point is \(k = 64\).
1Step 1: Identify the Condition
For the graph of the equation to be a point, the equation must represent a single point, which occurs when the radius is zero. This requires completing the square for the equation.
2Step 2: Rearrange the Equation
Start with the given equation: \(x^{2}+y^{2}-16x+k=0\). Collect the constant terms on one side: \(x^{2} - 16x + y^{2} = -k\).
3Step 3: Complete the Square for x
Consider the terms involving \(x\): \(x^{2} - 16x\). To complete the square, add and subtract \(8^2 = 64\), resulting in: \( (x - 8)^2 - 64 \).
4Step 4: Express the Equation in Standard Form
Substitute the completed square back into the equation: \((x - 8)^2 - 64 + y^2 = -k\). Simplify to get: \((x - 8)^2 + y^2 = 64 - k\).
5Step 5: Set the Radius to Zero
A point has a radius of zero. Therefore, set: \((x - 8)^2 + y^2 = 0\), which implies \(64 - k = 0\).
6Step 6: Solve for k
Solve \(64 - k = 0\) to find \(k\). You get \(k = 64\).
Key Concepts
Completing the SquareRadiusGraph of an Equation
Completing the Square
Completing the square is a handy technique used in algebra to transform a quadratic expression into a perfect square trinomial. This is significant when dealing with quadratic equations like those representing circles in the Cartesian coordinate system.
To complete the square, we follow these steps:
To complete the square, we follow these steps:
- Identify the quadratic expression in the form of \(x^2 + bx\).
- Take half of the coefficient of \(x\), square it, and add and subtract this square to the expression. This essentially means you have formed \((x - h)^2\) where \(h\) is half of the \(b\) coefficient.
- In our example, for the expression \(x^2 - 16x\), we have \(b = -16\). Taking half gives us \(-8\) and squaring it gives \(64\). So, we add and subtract \(64\) to complete the square, resulting in \((x - 8)^2 - 64\).
Radius
In the context of a circle, the radius is the distance from the center of the circle to any point on its circumference. In the Cartesian coordinate system, a circle's equation is typically written in the form \((x - h)^2 + (y - k)^2 = r^2\) where \((h, k)\) is the center of the circle and \(r\) is the radius.
To find whether the equation represents a circle and what its radius is:
To find whether the equation represents a circle and what its radius is:
- Ensure the equation is in the standard form of a circle.
- The expression \((x - h)^2 + (y - k)^2\) is set equal to \(r^2\), the square of the radius.
- From the completed formation \((x - 8)^2 + y^2 = 64 - k\), it's clear that the expression represents a circle because of the sum of squares form.
Graph of an Equation
Graphs of equations are visual representations in a coordinate system that illustrate all solutions of an equation. For example, a circle's equation graphically represents all the points equidistant from a center point. Different equations produce different graphs such as lines, parabolas, and circles.
In our specific exercise:
In our specific exercise:
- The initial equation is \(x^{2}+y^{2}-16x+k=0\), initially it's not clear what form it takes.
- Through completing the square, the equation was restructured to \((x - 8)^2 + y^2 = 64 - k\), indicating a potential circle graph.
- However, by determining the condition \(64 - k = 0\), we established the graph was not truly a circle but a singular point when \(k=64\).
Other exercises in this chapter
Problem 54
Find all polynomials \(p\) such that \((p \circ p)(x)=x\). Hint: What degree must \(p\) have?
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Identify the curve that is parameterized by the equations. In each case, use a trigonometric identity to eliminate the parameter. (It may help to consider the s
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Find a point \((a, b)\) so that the line through \((a, b)\) and (4,2) is parallel to the line through (3,6) and (2,9) .
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In this exercise, you will compute the first several terms of a sequence \(\left\\{m_{n}\right\\}\) of rational numbers that approach \(\sqrt{2}\). Let \(I_{1}\
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