Problem 54
Question
Components of a Velocity A jet is flying in a direction N \(20^{\circ} \mathrm{E}\) with a speed of \(500 \mathrm{mi} / \mathrm{h}\). Find the north and east components of the velocity.
Step-by-Step Solution
Verified Answer
North component: 469.8 mi/h, East component: 171.0 mi/h.
1Step 1: Understanding the Problem
The jet is flying in a direction of North 20° East. This means the angle is measured 20° towards the east from the north direction. We are given the jet's speed as 500 mi/h and need to find its northward (vertical) and eastward (horizontal) components of velocity.
2Step 2: Identify the Components
We need to find the north (vertical) and east (horizontal) components of the velocity using trigonometric functions. The northward component is found using the cosine function, and the eastward component is found using the sine function.
3Step 3: Find the North Component
The northward component of velocity can be calculated using the formula: \( V_{north} = V \cdot \cos(\theta) \), where \( V = 500 \mathrm{mi/h} \) and \( \theta = 20^{\circ} \).Thus, \( V_{north} = 500 \cdot \cos(20^{\circ}) \approx 469.8 \mathrm{mi/h} \).
4Step 4: Find the East Component
The eastward component of velocity can be calculated using the formula: \( V_{east} = V \cdot \sin(\theta) \), where \( V = 500 \mathrm{mi/h} \) and \( \theta = 20^{\circ} \).Thus, \( V_{east} = 500 \cdot \sin(20^{\circ}) \approx 171.0 \mathrm{mi/h} \).
5Step 5: Final Components
Both components of the velocity of the jet have been calculated:
- North component: approximately 469.8 mi/h
- East component: approximately 171.0 mi/h.
Key Concepts
Understanding Trigonometric Functions in PhysicsBreaking Down Vectors into ComponentsThe Concept of Velocity Decomposition
Understanding Trigonometric Functions in Physics
Trigonometric functions are mathematical tools that are commonly used to solve problems involving angles and dimensions. In physics, they are essential for breaking down vectors into their components. The two primary functions used for this purpose are sine and cosine.
These functions relate the angles of a right triangle to the lengths of its sides:
These functions relate the angles of a right triangle to the lengths of its sides:
- Sine function (\( ext{sin}\))— This is the ratio of the length of the side opposite the angle to the length of the hypotenuse.
- Cosine function (\( ext{cos}\))— This is the ratio of the length of the adjacent side to the hypotenuse.
Breaking Down Vectors into Components
Vectors are quantities that have both magnitude and direction. In many physics problems, such as the one with the jet, it is essential to break down a vector into its horizontal and vertical components.
To find these vector components, you can deploy trigonometric functions:
To find these vector components, you can deploy trigonometric functions:
- To find the horizontal component (eastward): Use the sine function: \(V_{east} = V \, \sin(\theta)\).
- To find the vertical component (northward): Use the cosine function: \(V_{north} = V \, \cos(\theta)\).
The Concept of Velocity Decomposition
Velocity decomposition is a fundamental concept in physics where a velocity vector is broken down into its perpendicular components. For a real-world application, consider a jet flying in any direction.
By decomposing its velocity, you define:
By decomposing its velocity, you define:
- Northward component: Tells how fast the jet is moving in the north direction, calculated using the cosine of the angle with the vertical.
- Eastward component: Measures the jet's speed moving towards the east, calculated using the sine of the angle with the vertical.
Other exercises in this chapter
Problem 52
Find the magnitude and direction (in degrees) of the vector. $$\mathbf{v}=\mathbf{i}+\mathbf{j}$$
View solution Problem 53
Components of a Force A man pushes a lawn mower with a force of 30 lb exerted at an angle of \(30^{\circ}\) to the ground. Find the horizontal and vertical comp
View solution Problem 55
Velocity A river flows due south at 3 mi/h. A swimmer attempting to cross the river heads due east swimming at \(2 \mathrm{mi} / \mathrm{h}\) relative to the wa
View solution Problem 57
Velocity The speed of an airplane is \(300 \mathrm{mi} / \mathrm{h}\) relative to the air. The wind is blowing due north with a speed of 30 \(\mathrm{mi} / \mat
View solution