Problem 54
Question
CITY PLANNING. City planners have laid out streets on a coordinate grid before beginning construction. One street lies on the line with equation \(y=2 x+1 .\) Another street that intersects the first street passes through the point \((2,-3)\) and is perpendicular to the first street. What is the equation of the line on which the second street lies?
Step-by-Step Solution
Verified Answer
Equation is \(y = -\frac{1}{2}x - 2\)
1Step 1: Understand the Slope of the First Street
The equation of the first street is given as \(y = 2x + 1\). This is in slope-intercept form \(y = mx + b\), where \(m\) is the slope. Therefore, the slope of the first street is 2.
2Step 2: Determine the Slope of the Perpendicular Line
Lines that are perpendicular have slopes that are negative reciprocals of each other. If the slope of the first street (m) is 2, then the slope (m') of the perpendicular line is \(-\frac{1}{2}\) because \(-\frac{1}{2}\) is the negative reciprocal of 2.
3Step 3: Use Point-Slope Formula
The equation of a line can be found using the point-slope formula: \(y - y_1 = m(x - x_1)\). Substitute the slope \(m = -\frac{1}{2}\) and the given point \((2,-3)\) into the formula. This gives: \[y + 3 = -\frac{1}{2}(x - 2)\]
4Step 4: Simplify to Slope-Intercept Form
Expand and simplify the equation: \[y + 3 = -\frac{1}{2}x + 1\]. To isolate \(y\), subtract 3 from both sides, giving \[y = -\frac{1}{2}x + 1 - 3\] which simplifies to \[y = -\frac{1}{2}x - 2\].
Key Concepts
Perpendicular LinesSlope-Intercept FormPoint-Slope Formula
Perpendicular Lines
Understanding perpendicular lines is crucial when working with coordinate geometry and city planning. Perpendicular lines intersect at a 90-degree angle. This unique property makes them particularly helpful in creating well-organized and navigable street grids.
In mathematical terms, when two lines are perpendicular, the product of their slopes is \(-1\). If you have the slope of one line, say \(m\), the slope of the perpendicular line will be the negative reciprocal, which is \(-\frac{1}{m}\). For example, if the slope of one line is 2, the slope of its perpendicular line will be \(-\frac{1}{2}\). This concept is a staple in coordinate geometry and invaluable for designing systems like city streets that need to meet at right angles.
In mathematical terms, when two lines are perpendicular, the product of their slopes is \(-1\). If you have the slope of one line, say \(m\), the slope of the perpendicular line will be the negative reciprocal, which is \(-\frac{1}{m}\). For example, if the slope of one line is 2, the slope of its perpendicular line will be \(-\frac{1}{2}\). This concept is a staple in coordinate geometry and invaluable for designing systems like city streets that need to meet at right angles.
Slope-Intercept Form
The slope-intercept form of a linear equation is perhaps the most intuitive way to describe a line on a coordinate plane. The equation is written as \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. This form is called "slope-intercept" because it visibly shows you the slope and the point where the line crosses the y-axis.
Here's why it's so useful:
Here's why it's so useful:
- The slope \(m\) tells you how steep the line is. A higher slope means a steeper line.
- The intercept \(b\) tells you where the line will cross the y-axis, making it handy for sketching graphs.
Point-Slope Formula
When you know a point on a line and the slope, the point-slope formula is your go-to tool. This formula is written as \(y - y_1 = m(x - x_1)\), where \(m\) is the slope and \((x_1, y_1)\) is a specific point on the line.
The point-slope formula is particularly handy when the line's equation needs to include a specific point. Here's how you use it:
The point-slope formula is particularly handy when the line's equation needs to include a specific point. Here's how you use it:
- Identify your slope \(m\) and the coordinates of your point \((x_1, y_1)\).
- Substitute these values into the formula to find the general equation of your line.
- From here, you can even convert it to slope-intercept form by solving for \(y\) to get \(y = mx + b\).
Other exercises in this chapter
Problem 53
Given \(f(x)=x^{2}-5 x+6,\) find each value. $$ f(-2) $$
View solution Problem 53
Graph each function. $$ y=\frac{1}{3}(x+5)^{2}-1 $$
View solution Problem 54
Simplify. $$ \left(3 x^{2}-2 x y+y^{2}\right)+\left(x^{2}+5 x y-4 y^{2}\right) $$
View solution Problem 54
Use synthetic substitution to find \(f(-3)\) and \(f(4)\) for each function. \(f(x)=x^{4}+11 x^{3}-3 x^{2}+2 x-5\)
View solution