Problem 53
Question
Write the negation of each statement. Express each negation in a form such that the symbol \(\sim\) negates only simple statements. \(p \wedge(r \rightarrow \sim s)\)
Step-by-Step Solution
Verified Answer
The negation of the statement \(p \wedge(r \rightarrow \sim s)\) is \(\sim p \vee (r \wedge s)\).
1Step 1: Understanding Compound Statement
The given compound statement includes different types of logical operators: conjunction(\(\wedge\)), conditional(\(\rightarrow\)), and negation(\(\sim\)). The statement actually says that 'p and (if r then not s)'.
2Step 2: Applying Negation and De Morgan's Law
The first step in negating the compound sentence is to apply the negation operator to the whole sentence. This will give us \(\sim (p \wedge (r \rightarrow \sim s))\). Next, we have to apply De Morgan's law. According to De Morgan's law, the negation of a conjunction is the disjunction of the negations, and the negation of a disjunction is the conjunction of the negations. Therefore, the negation of our compound sentence becomes \(\sim p \vee \sim (r \rightarrow \sim s)\).
3Step 3: Simplifying the Conditional Statement
The conditional statement \(r \rightarrow \sim s\) is equivalent to \(\sim r \vee \sim s\). So let's substitute this into our formula. Hence we obtain \(\sim p \vee (\sim (\sim r \vee \sim s))\). Applying De Morgan's law again gives \(\sim p \vee (r \wedge s)\).
4Step 4: Final Step
Finally, our compound statement has been simplified to entirely use the symbol \(\sim\) to negate only simple statements. The result is \(\sim p \vee (r \wedge s)\).
Key Concepts
Compound StatementDe Morgan's LawsLogical Operators
Compound Statement
A compound statement is a logical expression that combines two or more simple statements using logical operators. Each simple statement within a compound statement can be true or false on its own. For example, propositions "p" and "q" could individually be true or false; however, when they are joined, they create a more complex statement.
- The main logical operators used in compound statements are conjunction ( \( \wedge \)), disjunction (\( \vee \)), implication (\( \rightarrow \)), and negation (\( \sim \)).
- Conjunctions combine statements where both must be true for the whole statement to be true.
- Disjunctions are true if at least one component statement is true.
- Implication represents a conditional relationship, expressing "if...then..." scenarios.
- Negation inverts the truth value of a statement: if the original is true, its negation is false, and vice versa.
De Morgan's Laws
De Morgan's Laws are crucial in the world of logic because they allow us to rewrite logical expressions in different, often simpler forms. These laws deal specifically with negations within compound statements and provide a useful technique for transforming and simplifying complex logical expressions.
- The first law states that the negation of a conjunction is logically equivalent to the disjunction of the negations: \( \sim(p \wedge q) \equiv \sim p \vee \sim q \).
- The second law states that the negation of a disjunction is equivalent to the conjunction of the negations: \( \sim(p \vee q) \equiv \sim p \wedge \sim q \).
Logical Operators
Logical operators are symbols or words used to connect simple statements, allowing them to form compound statements. There are several key operators in logic that each perform specific functions to manipulate truth values in a compound statement.
- Conjunction (\( \wedge \)): Connects two statements and results in true only if both statements are true.
- Disjunction (\( \vee \)): Results in true if at least one of the statements is true.
- Implication (\( \rightarrow \)): Also known as a conditional, it indicates that if the first statement is true, then the second is true.
- Negation (\( \sim \)): Alters the truth value of a statement, making true statements false and vice versa.
Other exercises in this chapter
Problem 52
Let \(p\) and \(q\) represent the following simple statements: p: Romeo loves Juliet. q: Juliet loves Romeo. Write each symbolic statement in words. \(\sim q \w
View solution Problem 53
Translate each argument into symbolic form. Then determine whether the argument is valid or invalid. It is the case that \(x8\), but \(x \geq 5\), so \(x>8\).
View solution Problem 53
Use a truth table to determine whether each statement is a tautology, a self- contradiction, or neither. \([(p \rightarrow q) \wedge(q \rightarrow r)] \rightarr
View solution Problem 53
Determine the truth value for each statement when \(p\) is false, \(q\) is true, and \(r\) is false. \(p \wedge(q \vee r)\)
View solution