Problem 53
Question
Write the ionization equation for a weak acid and the equation for its conjugate base reaction with water. Show that adding these two equations gives the autoionization equation for water.
Step-by-Step Solution
Verified Answer
Adding the weak acid ionization and conjugate base reaction gives water's autoionization equation: \( 2\text{H}_2\text{O} \rightleftharpoons \text{H}_3\text{O}^+ + \text{OH}^- \).
1Step 1: Write the Ionization Equation for Weak Acid
Consider a weak acid, represented as HA. When it dissolves in water, it partially ionizes into its conjugate base, A⁻, and a H⁺ ion. The equation for this ionization is: \[ \text{HA(aq)} + \text{H}_2\text{O} \rightleftharpoons \text{H}_3\text{O}^+ + \text{A}^- \].
2Step 2: Write the Equation for Conjugate Base Reaction
The conjugate base of the weak acid, A⁻, can react with water to reform the weak acid and produce hydroxide ions \( \text{OH}^- \). The equation for this reaction is: \[ \text{A}^- + \text{H}_2\text{O} \rightleftharpoons \text{HA(aq)} + \text{OH}^- \].
3Step 3: Add the Two Equations
Add the two equations from Steps 1 and 2 together. The equations are:\( \text{HA(aq)} + \text{H}_2\text{O} \rightleftharpoons \text{H}_3\text{O}^+ + \text{A}^- \) and \( \text{A}^- + \text{H}_2\text{O} \rightleftharpoons \text{HA(aq)} + \text{OH}^- \).When added together, the \( \text{HA(aq)} \) and \( \text{A}^- \) terms cancel each other out, leading to the equation: \[ \text{2H}_2\text{O} \rightleftharpoons \text{H}_3\text{O}^+ + \text{OH}^- \].
4Step 4: Interpretation of the Result
The resulting equation, \( \text{2H}_2\text{O} \rightleftharpoons \text{H}_3\text{O}^+ + \text{OH}^- \), is the well-known autoionization of water equation, which shows that water can ionize into hydronium and hydroxide ions, maintaining a balance of hydrogen ion concentration.
Key Concepts
Conjugate Base ReactionAutoionization of WaterChemical Equilibrium
Conjugate Base Reaction
In chemistry, when we talk about a conjugate base, it's the form that remains after an acid has donated a hydrogen ion (H⁺). In the case of a weak acid like HA, when it ionizes in water, it forms its conjugate base, A⁻, along with a hydronium ion (H₃O⁺).
In the conjugate base reaction, this A⁻ doesn't just sit around. Rather, it has the potential to interact with water again. During this interaction, it picks up a hydrogen ion from the water. This gives rise to the original weak acid (HA) and a hydroxide ion (OH⁻).
In simplified terms, think of it as a reversible dance between the acid, its conjugate base, and water. They swap partners and roles, which keeps the system lively and in balance! The equation for this reaction is:
In the conjugate base reaction, this A⁻ doesn't just sit around. Rather, it has the potential to interact with water again. During this interaction, it picks up a hydrogen ion from the water. This gives rise to the original weak acid (HA) and a hydroxide ion (OH⁻).
In simplified terms, think of it as a reversible dance between the acid, its conjugate base, and water. They swap partners and roles, which keeps the system lively and in balance! The equation for this reaction is:
- A⁻ + H₂O ↔ HA(aq) + OH⁻
Autoionization of Water
Water is unique. It has the ability to ionize on its own in a phenomenon known as autoionization. This is where two molecules of water interact with each other.
One water molecule donates a hydrogen ion to the other, forming a hydronium ion (H₃O⁺) and a hydroxide ion (OH⁻). This is a reversible reaction, and thus it's a dynamic process that is constantly occurring in water.
One water molecule donates a hydrogen ion to the other, forming a hydronium ion (H₃O⁺) and a hydroxide ion (OH⁻). This is a reversible reaction, and thus it's a dynamic process that is constantly occurring in water.
- The overall equation for this process is: 2H₂O ↔ H₃O⁺ + OH⁻
Chemical Equilibrium
Chemical equilibrium is a state where the forward and reverse reactions happen at equal rates. In such a state, the concentrations of the reactants and products remain constant over time.
Take the example of a weak acid in water. The acid, HA, partially ionizes to produce hydronium ions (H₃O⁺) and its conjugate base (A⁻).
Simultaneously, the conjugate base can revert back to the acid by reacting with water, forming hydroxide ions. Even though both reactions continue to happen, they do so at the same rate, leading to a stable balance.
Take the example of a weak acid in water. The acid, HA, partially ionizes to produce hydronium ions (H₃O⁺) and its conjugate base (A⁻).
Simultaneously, the conjugate base can revert back to the acid by reacting with water, forming hydroxide ions. Even though both reactions continue to happen, they do so at the same rate, leading to a stable balance.
- The reactions can be represented as:
- HA(aq) + H₂O ↔ H₃O⁺ + A⁻
- A⁻ + H₂O ↔ HA(aq) + OH⁻
- Adding these equations results in the autoionization of water equation: 2H₂O ↔ H₃O⁺ + OH⁻
Other exercises in this chapter
Problem 51
Write stepwise chemical equations for protonation or deprotonation of each of these polyprotic acids and bases in water. (a) \(\mathrm{CO}_{3}^{2-}\) (b) \(\mat
View solution Problem 52
Write stepwise chemical equations for protonation or deprotonation of each of these polyprotic acids and bases in water. (a) \(\mathrm{H}_{2} \mathrm{SO}_{3}\)
View solution Problem 56
Calculate the \(K_{\mathrm{a}}\) of butyric acid if a \(0.025-\mathrm{M}\) butyric acid solution has a pH of 3.21 .
View solution Problem 57
The pH of a 0.10-M solution of propanoic acid, \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH},\) a weak organic acid, is measured at equilibrium and found to b
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