Problem 53
Question
Which would you expect to be the more ductile element, (a) \(\mathrm{Ag}\) or \(\mathrm{Cr}\), (b) \(\mathrm{Zn}\) or Ge? In each case explain your reasoning.
Step-by-Step Solution
Verified Answer
Silver (Ag) is more ductile than chromium (Cr), and zinc (Zn) is more ductile than germanium (Ge).
1Step 1: Understanding Ductility
Ductility is the ability of a material to deform under tensile stress, often characterized by the material's ability to be stretched into a wire. Materials that are more ductile typically have a more malleable atomic structure.
2Step 2: Evaluate Silver (Ag) versus Chromium (Cr)
Silver (Ag) is a transition metal known for its high ductility, as it allows for significant atomic displacement without breaking. Chromium (Cr), also a transition metal, is harder and less ductile due to its more rigid atomic structure. Generally, metals with more metallic bonding and fewer electron clouds are more ductile, making Ag more ductile than Cr.
3Step 3: Analyze Zinc (Zn) versus Germanium (Ge)
Zinc (Zn) is a metal with moderate ductility and is more ductile than germanium (Ge), which is a metalloid and has more covalent characteristics. Metals tend to have layers of atoms that can slide past each other more easily under stress, whereas metalloids like germanium have more directional bonds that are less favorable for ductility.
Key Concepts
Atomic Structure and BondingTransition MetalsMetallic BondingMetalloids vs Metals
Atomic Structure and Bonding
Understanding ductility requires a look into atomic structure and bonding. Ductility is determined by how atoms within a material interact and maintain their positions under stress.
Metals typically possess a unique atomic structure that allows atoms to slide over one another without breaking bonds. This is because metallic bonding involves a "sea" of electrons that act as a glue allowing atoms to be more malleable.
When a tensile force is applied, these atoms can be repositioned within the structure and still retain the integrity of the material, which is why metals like silver are so ductile. Non-metals and some metalloids, on the other hand, often have covalent bonding, which is more directional and less forgiving under stress.
Transition Metals
Transition metals, such as silver and chromium, are well-known for their range of mechanical properties, including ductility. These elements have a d-block on the periodic table, which means they have partially filled d orbitals.
- The electrons in these orbitals allow for a binding quality that maintains structural integrity through metallic bonding rather than directional, gap-based bonding.
- Silver is particularly ductile, owing to its ability to sustain a sea of moving electrons and metallic bonds that withstand tensile stress without losing coherence.
- Chromium, although a transition metal, has a denser atomic lattice that is more rigid, making it less ductile.
Metallic Bonding
Metallic bonding is the driving force behind the ductility of metals. Unlike covalent or ionic bonds that rely on directionality or fixed charges respectively, metallic bonding consists of free-moving electrons in a lattice of positively charged ions.
- This 'electron sea' model is characterized by the delocalized movement of electrons that allows layers of atoms to slip over one another.
- Metals like silver and zinc exhibit high ductility, as the electron sea provides flexibility to the atomic structure.
Metalloids vs Metals
The comparative study of metalloids and metals reveals why metals generally exhibit more ductility. Metals, like zinc, have a defined structure under metallic bonding, allowing atoms to shift without breaking the overall structure.
- Metals are characterized by their 'electron sea', that emphasizes atomic movement.
- Metalloids, such as germanium, find themselves as contenders between metals and non-metals, often exhibiting less ductility due to more directional covalent bonding.
Other exercises in this chapter
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Arrange the following metals in increasing order of expected melting point: \(\mathrm{La}, \mathrm{W}, \mathrm{Ta}\), Hf. Explain this trend in melting points.
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