Problem 53
Question
Use the sum-of-two-cubes or the difference-of-two-cubes pattern to factor each of the following. $$x^{3} y^{3}-1$$
Step-by-Step Solution
Verified Answer
The factored form is \((xy - 1)(x^2y^2 + xy + 1)\).
1Step 1: Recognize the Form
The expression \( x^3 y^3 - 1 \) matches the difference of cubes pattern, which is generally \( a^3 - b^3 \). Identify \( a \) and \( b \) such that \( (x^3 y^3) - 1 = (a^3) - (b^3) \). Here, let \( a = xy \) and \( b = 1 \).
2Step 2: Apply the Difference of Cubes Formula
For any difference of cubes \( a^3 - b^3 \), the factorization formula is \( (a - b)(a^2 + ab + b^2) \). Using \( a = xy \) and \( b = 1 \), substitute into the formula to get the factorization: \((xy - 1)((xy)^2 + (xy)(1) + 1^2)\).
3Step 3: Simplify the Factors
Simplify the expression \((xy - 1)((xy)^2 + (xy)(1) + 1)\). Calculate \((xy)^2 = x^2y^2\) and recall that \((1)^2 = 1\). Then the expression becomes \(xy - 1)(x^2y^2 + xy + 1)\).
4Step 4: Confirm the Factorization
Verify the factorization by expanding \((xy - 1)(x^2y^2 + xy + 1)\). Ensure that the expansion equals the original expression \(x^3 y^3 - 1\). The expansion should simplify correctly to confirm the factorization.
Key Concepts
Difference of CubesAlgebraFactoring Polynomials
Difference of Cubes
In algebra, recognizing patterns can make factoring easier. The difference of cubes is one such pattern. When a polynomial looks like two cubic terms subtracted from one another, you might be able to use this method. The general form for the difference of cubes is:
- \( a^3 - b^3 \)
- \( (a - b)(a^2 + ab + b^2) \)
Algebra
Algebra is the branch of mathematics that deals with symbols and the rules for manipulating these symbols. It's about finding the unknown or putting real-world variables into equations and then solving them. In algebra, we use letters to represent variables. This allows us to create general formulas that work in many situations.One of the powerful tools in algebra is recognizing and using patterns. Patterns like the difference of cubes help simplify polynomial expressions. With such tools, complex equations become manageable. The factorization of \( x^3 y^3 - 1 \) demonstrates how algebraic techniques can simplify expressions to their core components.
Factoring Polynomials
Factoring polynomials is the process of breaking down a polynomial into simpler components, or factors, that, when multiplied together, yield the original polynomial. This is an essential skill in algebra as it can simplify equations and make solving them easier.For polynomials that fit specific patterns, like the difference of cubes, shortcuts and formulas are available. The task is to recognize these patterns in the polynomial, apply the correct formula, and simplify the expressions.
- For example, \( x^3 y^3 - 1 \) can be seen as a difference of cubes.
- We use the formula \( (a - b)(a^2 + ab + b^2) \) with \( a = xy \) and \( b = 1 \).
Other exercises in this chapter
Problem 53
Solve each equation. You will need to use the factoring techniques that we discussed throughout this chapter. $$4 a(a+1)=3$$
View solution Problem 53
Factor completely each of the polynomials and indicate any that are not factorable using integers. $$18 n^{4}+25 n^{2}-3$$
View solution Problem 53
Factor by grouping. $$2 a x+2 x+a y+y$$
View solution Problem 53
Find each indicated product. Remember the shortcut for multiplying binomials and the other special patterns we discussed in this section. $$(t+3)\left(t^{2}-3 t
View solution