Problem 53
Question
The value of the integral \(\int_{1}^{e}\left[\frac{\log x}{3}\right] d x\), where \([\cdot]\) denotes the greatest integer function, is (A) 0 (B) \(e^{6}-e^{3}\) (C) \(e^{6}+e^{3}\) (D) \(e^{3}-e^{6}\)
Step-by-Step Solution
Verified Answer
The integral evaluates to 0, which is option (A).
1Step 1: Understanding the Greatest Integer Function
The greatest integer function, represented as \( [\log x/3] \), returns the largest integer less than or equal to the value of \( \log x/3 \). This means we need to find intervals where \( \log x/3 \) is an integer value or crosses an integer boundary.
2Step 2: Determine the Integer Ranges
We evaluate \( \log x = \log 1 = 0 \) at \( x = 1 \) and \( \log x = 1 \) at \( x = e \). Therefore, at \( x = 1 \), \( \log x/3 = 0 \), and \( x = e \), \( \log x/3 = 1/3 \). In the interval \( [1, e] \), \( [\log x/3] = 0 \) since the value 1/3 for \( x = e \) is still rounded down to 0.
3Step 3: Evaluate the Integral
Since \( [\log x/3] = 0 \) over the entire interval from 1 to \( e \), the integral simplifies to \( \int_{1}^{e} 0 \, dx = 0 \).
4Step 4: Select the Correct Option
Based on our evaluation in previous steps, the integral evaluates to 0, which corresponds to option (A).
Key Concepts
Greatest Integer FunctionLogarithmic FunctionsCalculus Problems
Greatest Integer Function
The greatest integer function, often denoted by the symbol \(\lfloor \cdot \rfloor\), returns the largest integer that is less than or equal to a given number. This means, for any real number \(x\), \(\lfloor x \rfloor\) is the greatest integer which is either equal to or less than \(x\). For example:
When dealing with functions like \([\frac{\log x}{3}]\), the aim is to find integer values within specific ranges.
In the provided exercise, knowing that \(\log x\) changes continuously with \(x\), the intervals where \([\frac{\log x}{3}]\) changes integer values need to be identified. The rounding down at integer boundaries provides insight into how the function behaves across an interval, simplifying the integration process.
- \(\lfloor 2.7 \rfloor = 2\)
- \(\lfloor -1.3 \rfloor = -2\)
When dealing with functions like \([\frac{\log x}{3}]\), the aim is to find integer values within specific ranges.
In the provided exercise, knowing that \(\log x\) changes continuously with \(x\), the intervals where \([\frac{\log x}{3}]\) changes integer values need to be identified. The rounding down at integer boundaries provides insight into how the function behaves across an interval, simplifying the integration process.
Logarithmic Functions
Logarithmic functions involve the logarithm, which is the inverse of exponentiation. The base of the logarithm is pivotal in determining the nature of the function. The common logarithm, \(\log\), is typically base 10, but in calculus, the natural logarithm, denoted as \(\ln x\), or \(\log x\) with base \(e\), is most common.
The fundamental property of logarithms that assists in solving calculus problems is that \(\log (a \cdot b) = \log a + \log b\). This property highlights the logarithm's ability to transform multiplication into addition, simplifying the process of integration and differentiation.
In the exercise, \(\log x\) with natural base \(e\) is employed. Here, \(x = 1\) results in \(\log 1 = 0\), and \(x = e\) results in \(\log e = 1\). Understanding these basic transformations is key in analyzing how the function behaves across its domain and lays the groundwork for applying other calculus concepts effectively.
The fundamental property of logarithms that assists in solving calculus problems is that \(\log (a \cdot b) = \log a + \log b\). This property highlights the logarithm's ability to transform multiplication into addition, simplifying the process of integration and differentiation.
In the exercise, \(\log x\) with natural base \(e\) is employed. Here, \(x = 1\) results in \(\log 1 = 0\), and \(x = e\) results in \(\log e = 1\). Understanding these basic transformations is key in analyzing how the function behaves across its domain and lays the groundwork for applying other calculus concepts effectively.
Calculus Problems
Problems in calculus often require a blend of techniques from both integration and differentiation. Here, we focus on the integration aspect, particularly definite integrals. A definite integral \(\int_{a}^{b} f(x) \, dx\) computes the area under the curve of \(f(x)\), from \(x = a\) to \(x = b\).
In this exercise, the function is \(\left[\frac{\log x}{3}\right]\), which incorporates the greatest integer function. The challenge is to accurately account for the intervals wherein this function maintains constant integer values across the integration domain.
To evaluate such integrals, identify intervals over which the function within the brackets doesn't change its integer value, then integrate this constant value over the interval's length. Solving these problems typically involves first simplifying the function within the integral to better understand its behavior over the specified domain.
In this exercise, the function is \(\left[\frac{\log x}{3}\right]\), which incorporates the greatest integer function. The challenge is to accurately account for the intervals wherein this function maintains constant integer values across the integration domain.
To evaluate such integrals, identify intervals over which the function within the brackets doesn't change its integer value, then integrate this constant value over the interval's length. Solving these problems typically involves first simplifying the function within the integral to better understand its behavior over the specified domain.
Other exercises in this chapter
Problem 51
The value of \(c\) for which the area of the figure bounded by the curve \(y=8 x^{2}-x^{5}\), the straight lines \(x=1\) and \(x\) \(=c\) and the \(x\)-axis is
View solution Problem 52
Let \(f(x)\) be a continuous function such that the area bounded by the curve \(y=f(x), x\)-axis and the lines \(x=0\) and \(x=a\) is \(\frac{a^{2}}{2}+\frac{a}
View solution Problem 54
If \(\int_{a}^{b}|\sin x| d x=8\) and \(\int_{a}^{a+b}|\cos x| d x=\frac{9}{2}\), then \(a\) is equal to: (A) \(\frac{\pi}{2}\) (B) \(\pi\) (C) \(\frac{\pi}{4}\
View solution Problem 56
Let \(f(x)=\max \\{x+|x|, x-[x]\\}\), where \([x]\) denotes the greatest integer less than or equal to \(x\), then \(\int_{-2}^{2} f(x) d x\) is equal to (A) 1
View solution