Problem 53
Question
Solve each equation. See Section \(2.3 .\) \(5(x-3)+3 x=1\)
Step-by-Step Solution
Verified Answer
The solution is \(x = 2\).
1Step 1: Distribute the 5
First, apply the distributive property to expand the expression on the left-hand side of the equation. Multiply 5 by both terms inside the parentheses: \[ 5(x - 3) + 3x = 1 \] Becomes: \[ 5x - 15 + 3x = 1 \]
2Step 2: Combine like terms
Next, combine the like terms on the left-hand side of the equation. The terms \(5x\) and \(3x\) are like terms. Add them together:\[ 8x - 15 = 1 \]
3Step 3: Isolate the variable term
Add 15 to both sides of the equation to isolate the term with the variable on one side:\[ 8x - 15 + 15 = 1 + 15 \] This simplifies to: \[ 8x = 16 \]
4Step 4: Solve for x
Finally, divide both sides by 8 to solve for \(x\):\[ \frac{8x}{8} = \frac{16}{8} \] This reduces to: \[ x = 2 \]
Key Concepts
Distributive PropertyCombining Like TermsIsolating the VariableAlgebraic Manipulation
Distributive Property
The distributive property is an essential concept in solving linear equations, especially when dealing with parentheses.When you see an expression like \(5(x - 3)\), you need to multiply the 5 by each term inside the parentheses. In this case, that means distributing 5 to both \(x\) and -3.
Distributing helps simplify equations, making it easier to work with individual terms.
- Multiply 5 by \(x\) to get \(5x\).
- Multiply 5 by -3 to get -15.
Distributing helps simplify equations, making it easier to work with individual terms.
Combining Like Terms
Once you've distributed, the next step is to combine like terms. Like terms are terms that have the same variable raised to the same power.In the equation \(5x - 15 + 3x = 1\), \(5x\) and \(3x\) are like terms.
Combining like terms helps reduce the number of terms, making the equation easier to solve.
- Identify terms with the same variable, like \(5x\) and \(3x\).
- Add their coefficients: \(5 + 3 = 8\).
Combining like terms helps reduce the number of terms, making the equation easier to solve.
Isolating the Variable
Isolating the variable is a crucial step in solving any equation. The goal is to get the variable by itself on one side of the equation.In the equation \(8x - 15 = 1\), you want \(x\) alone.
To do this, perform operations that maintain the equation's balance.
Isolating the variable sets you up perfectly for the final step.
To do this, perform operations that maintain the equation's balance.
- Add 15 to both sides: \(8x - 15 + 15 = 1 + 15\).
- This simplifies to \(8x = 16\).
Isolating the variable sets you up perfectly for the final step.
Algebraic Manipulation
Algebraic manipulation ties all the previous steps together to solve the equation.Once the variable is isolated, you're ready for final operations.In \(8x = 16\), divide both sides by 8 to solve for \(x\).
- Divide: \(\frac{8x}{8} = \frac{16}{8}\).
- This simplifies to \(x = 2\).
Other exercises in this chapter
Problem 53
When solving a system of equations by the addition method, how do we know when the system has no solution?
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Use a graphing calculator to solve each system. $$ \left\\{\begin{array}{l} y=5.1 x+14.56 \\ y=-2 x-3.9 \end{array}\right. $$
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Explain why the addition method might be preferred over the substitution method for solving the system \(\left\\{\begin{array}{l}2 x-3 y=5 \\ 5 x+2 y=6\end{arra
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