Problem 53
Question
Solve each equation for \(x\) in terms of the other letters. $$\frac{1}{x}=a+b$$
Step-by-Step Solution
Verified Answer
\( x = \frac{1}{a + b} \)
1Step 1: Identify the Given Equation
The given equation is \( \frac{1}{x} = a + b \), where we need to solve for \( x \) in terms of \( a \) and \( b \).
2Step 2: Clear the Fraction
To eliminate the fraction, multiply both sides of the equation by \( x \). This gives us \( 1 = (a + b)x \).
3Step 3: Isolate the Variable x
Divide both sides of the equation by \( a + b \) to solve for \( x \). This results in \( x = \frac{1}{a + b} \).
Key Concepts
Algebra: Understanding the BasicsFraction Elimination: Simplifying EquationsVariable Isolation: Solving for the Unknown
Algebra: Understanding the Basics
Algebra is a branch of mathematics dealing with symbols and the rules for manipulating those symbols. It's like a language that helps us represent problems and solve equations systematically.
In algebra, we often use letters such as \( x \), \( a \), and \( b \) to stand for numbers. These letters are called variables. They enable us to create expressions and equations that can describe a wide variety of problems and scenarios.When working with algebraic expressions and equations, the goal is often to isolate one variable, solving it in terms of others. This involves applying different algebraic rules and operations, such as addition, subtraction, multiplication, and division. Remember, keeping each side of an equation balanced is crucial. Every operation you perform on one side must also be performed on the other. This ensures the equation remains true.
In algebra, we often use letters such as \( x \), \( a \), and \( b \) to stand for numbers. These letters are called variables. They enable us to create expressions and equations that can describe a wide variety of problems and scenarios.When working with algebraic expressions and equations, the goal is often to isolate one variable, solving it in terms of others. This involves applying different algebraic rules and operations, such as addition, subtraction, multiplication, and division. Remember, keeping each side of an equation balanced is crucial. Every operation you perform on one side must also be performed on the other. This ensures the equation remains true.
Fraction Elimination: Simplifying Equations
A common challenge in algebra is dealing with equations that contain fractions. These can make otherwise simple equations seem complicated. But, with a few techniques, we can eliminate fractions with ease.
To clear a fraction, find the least common denominator or use multiplication. For example, if you have the equation \( \frac{1}{x} = a + b \), multiplying both sides by \( x \) will cancel out the fraction, simplifying the equation to \( 1 = (a + b)x \).
By multiplying both sides by the variable in the denominator (in this case, \( x \)), you effectively "clear" the fraction. This step is often crucial in making the equation easier to solve. Always double-check that the operation is valid and won't lead to division by zero. This can happen if the variable you multiply by turns out to be zero.
To clear a fraction, find the least common denominator or use multiplication. For example, if you have the equation \( \frac{1}{x} = a + b \), multiplying both sides by \( x \) will cancel out the fraction, simplifying the equation to \( 1 = (a + b)x \).
By multiplying both sides by the variable in the denominator (in this case, \( x \)), you effectively "clear" the fraction. This step is often crucial in making the equation easier to solve. Always double-check that the operation is valid and won't lead to division by zero. This can happen if the variable you multiply by turns out to be zero.
Variable Isolation: Solving for the Unknown
Once fractions are cleared from an equation, the next step is to isolate the variable you need to solve for. This process involves rearranging the equation until the variable is alone on one side.
In our equation \( 1 = (a + b)x \), the next step is to get \( x \) by itself. This requires dividing both sides by \( a + b \). This operation reveals our solution: \( x = \frac{1}{a + b} \). The key here is to ensure that you perform arithmetic operations correctly and apply them to both sides of the equation. Variable isolation is often the final step in solving an algebraic equation. Once isolated, you have expressed the unknown variable in terms of other known variables or constants in the problem. This is the point at which the problem is considered solved unless additional steps are specified.
In our equation \( 1 = (a + b)x \), the next step is to get \( x \) by itself. This requires dividing both sides by \( a + b \). This operation reveals our solution: \( x = \frac{1}{a + b} \). The key here is to ensure that you perform arithmetic operations correctly and apply them to both sides of the equation. Variable isolation is often the final step in solving an algebraic equation. Once isolated, you have expressed the unknown variable in terms of other known variables or constants in the problem. This is the point at which the problem is considered solved unless additional steps are specified.
Other exercises in this chapter
Problem 53
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