Problem 53
Question
Perform the operations. Simplify, if possible. $$ \frac{c}{7 c-d}-\frac{d}{d-7 c} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \(\frac{c + d}{7c-d}\).
1Step 1: Recognize Identical Denominators
Observe that the two denominators, \(7c - d\) and \(d - 7c\), are opposites of each other. Specifically, \(d - 7c = -(7c - d)\). This means they will simplify upon combining the fractions.
2Step 2: Rewrite the Second Fraction
Convert the second fraction, \(-\frac{d}{d-7c}\), by recognizing that \(d - 7c = -(7c - d)\). Thus, we can rewrite the second fraction as \(\frac{d}{-(7c - d)} = \frac{-d}{7c-d}\).
3Step 3: Combine the Fractions
Now that both fractions have the same denominator, \(7c-d\), subtract the second fraction from the first: \(\frac{c}{7c-d} - \frac{-d}{7c-d} = \frac{c + d}{7c-d}\).
4Step 4: Simplify the Expression
Check to see if any further simplifications can be made with the expression \(\frac{c + d}{7c-d}\). In this case, \(c+d\) and \(7c-d\) do not share any common factors, so the expression is already in its simplest form.
Key Concepts
Understanding Opposite DenominatorsThe Art of Fraction SimplificationCombining Fractions with Confidence
Understanding Opposite Denominators
When dealing with algebraic fractions, identifying opposite denominators is key. Opposite denominators appear when you have two expressions in the denominator that are negative inverses of each other. For example, the denominators \(7c - d\) and \(d - 7c\) are opposites. We can express this relationship algebraically: \(d - 7c = -(7c - d)\).
Understanding this concept helps simplify the process of combining these fractions because recognizing opposite denominators allows you to manipulate fractions into a common form.
Understanding this concept helps simplify the process of combining these fractions because recognizing opposite denominators allows you to manipulate fractions into a common form.
- This is crucial for combining fractions effectively.
- Knowing how to identify and handle opposite denominators saves you time in algebraic manipulation.
The Art of Fraction Simplification
Fraction simplification in algebra is all about reducing expressions to their simplest form while ensuring equivalent values. When you simplify a fraction, you look to cancel common factors in the numerator and the denominator. For instance, in the expression \(\frac{c + d}{7c-d}\), check the numerator and the denominator for common factors.
In this case, both parts, \(c + d\) and \(7c - d\), have no common factors, which means the fraction is already simplified. A fraction is fully simplified when:
In this case, both parts, \(c + d\) and \(7c - d\), have no common factors, which means the fraction is already simplified. A fraction is fully simplified when:
- Numerator and denominator have no common factors besides 1.
- You can't divide both by the same variable or constant to get simpler numbers.
Combining Fractions with Confidence
Combining fractions is a fundamental skill in algebra that allows you to add or subtract fractions with different parts effectively. Before combining fractions, the denominators must be the same, which might involve rewriting one or both fractions.
Once you standardize the denominators, as shown when we rewrote \(-\frac{d}{d-7c}\) to \(\frac{-d}{7c-d}\), combining them becomes straightforward: - Subtract the numerators: \( \frac{c}{7c-d} - \frac{-d}{7c-d} \)- Calculate: \( \frac{c + d}{7c-d} \)
The key processes involve:
Once you standardize the denominators, as shown when we rewrote \(-\frac{d}{d-7c}\) to \(\frac{-d}{7c-d}\), combining them becomes straightforward: - Subtract the numerators: \( \frac{c}{7c-d} - \frac{-d}{7c-d} \)- Calculate: \( \frac{c + d}{7c-d} \)
The key processes involve:
- Changing opposite denominators to a common denominator.
- Adding or subtracting numerators directly.
Other exercises in this chapter
Problem 52
Find the LCD of pair of rational expressions. \(\frac{b^{2}-b}{10 b-15}, \frac{11 b}{10}\)
View solution Problem 52
Divide, and then simplify, if possible. \(\frac{x^{2}-10 x}{7 x+7} \div \frac{(x-10)^{2}}{35 x+35}\)
View solution Problem 53
Sales. A dealer bought some radios for a total of $$ 1,200 .\( She gave away 6 radios as gifts, sold the rest for $$ 10\) more than she paid for each radio, and
View solution Problem 53
Simplify each complex fraction. $$ \frac{\frac{1}{c}+\frac{1}{2}}{\frac{1}{c^{2}}-\frac{1}{4}} $$
View solution