Problem 53
Question
Name all of the sets of numbers to which each real number belongs. Let \(N=\) natural numbers, \(\mathbf{W}=\) whole numbers, \(\mathbf{Z}=\) integers, \(\mathbf{Q}=\) rational numbers, and $\mathbf{I}=\text { irrational numbers. $$\sqrt{63}$$
Step-by-Step Solution
Verified Answer
\( \sqrt{63} \) belongs to the set of irrational numbers, \( \mathbf{I} \).
1Step 1: Understand the Number
The number given is \( \sqrt{63} \). We need to determine its exact value to categorize it into different sets. Since \( \sqrt{63} \) is not a perfect square, it is approximately equal to 7.94, and it cannot be expressed as an exact fraction.
2Step 2: Determine if it Belongs to Natural Numbers (N)
Natural numbers are counting numbers, starting from 1 onwards (1, 2, 3,...). Since \( \sqrt{63} \) is not a whole number and not even an integer, it does not belong to the natural numbers.
3Step 3: Determine if it Belongs to Whole Numbers (W)
Whole numbers include all natural numbers and zero (0, 1, 2, 3,...). Since \( \sqrt{63} \) is not a whole number, it does not belong to whole numbers.
4Step 4: Determine if it Belongs to Integers (Z)
Integers include all whole numbers and their negatives (-3, -2, -1, 0, 1, 2,...). Since \( \sqrt{63} \) is not an integer, it is not included in the set of integers.
5Step 5: Determine if it Belongs to Rational Numbers (Q)
Rational numbers are numbers that can be expressed as a fraction of two integers. \( \sqrt{63} \) cannot be exactly expressed as a fraction and has a non-terminating, non-repeating decimal expansion, thus it is not a rational number.
6Step 6: Determine if it Belongs to Irrational Numbers (I)
Irrational numbers cannot be expressed as a fraction, and they have non-repeating, non-terminating decimals. Since \( \sqrt{63} \) meets these criteria (it's not a perfect square and not expressible as a fraction), it is an irrational number.
Key Concepts
Natural NumbersWhole NumbersIntegersRational NumbersIrrational Numbers
Natural Numbers
Natural numbers are the simplest set of numbers. They start from 1 and continue upwards to infinity. Think of them as the numbers you first learned to count. So, when you think of natural numbers, you just imagine counting objects like 1 apple, 2 apples, and so on.
- They are also known as counting numbers.
- Natural numbers include numbers like 1, 2, 3, 4, etc.
Whole Numbers
Whole numbers make up an extended set including all natural numbers and the number 0.
- Whole numbers start from 0 and extend infinitely in the positive direction: 0, 1, 2, 3, and so on.
- They do not include fractions, decimals, or negative numbers.
Integers
Integers broaden the concept further by including negative numbers. They encompass positive whole numbers, zero, and their negative counterparts.
- Examples include -3, -2, -1, 0, 1, 2, 3, etc.
- The set of integers is infinite in both the positive and negative directions.
Rational Numbers
Rational numbers represent a broader set of numbers that includes fractions. A rational number can be expressed as the quotient or fraction of two integers (a/b), where 'a' and 'b' are both integers, and 'b' is not zero.
- They include numbers like 1/2, -4/3, and even numbers like 5 (which can be written as 5/1).
- Rational numbers have either terminating or repeating decimal expansions.
Irrational Numbers
Irrational numbers are a unique set of numbers that cannot be expressed as a simple fraction of two integers. They have non-terminating, non-repeating decimal expansions. This means they go on forever without a repeating pattern.
- Common examples include \(\pi\) and \(\sqrt{2}\).
- Irrational numbers cannot be exactly written as a fraction.
Other exercises in this chapter
Problem 52
Name all of the sets of numbers to which each real number belongs. Let \(N=\) natural numbers, \(\mathbf{W}=\) whole numbers, \(\mathbf{Z}=\) integers, \(\mathb
View solution Problem 52
Solve each equation. Round to the nearest tenth, if necessary. $$m^{2}=81$$
View solution Problem 53
Solve each inequality. $$4 y>24$$
View solution Problem 53
Solve each equation. Round to the nearest tenth, if necessary. $$196=y^{2}$$
View solution