Problem 53
Question
Multiply. Write your answers in the form \(a+b i\). $$ (1-i)^{2} $$
Step-by-Step Solution
Verified Answer
The expression \((1-i)^{2}\) simplifies to \(-2i\).
1Step 1: Expand the Expression
To solve the expression \((1-i)^2\), let's first expand it. Use the algebraic identity \((a-b)^2 = a^2 - 2ab + b^2\). Here, your \(a = 1\) and \(b = i\).
2Step 2: Calculate Each Term
Plug \(a = 1\) and \(b = i\) into the identity: \[ (1-i)^2 = 1^2 - 2(1)(i) + i^2 \] Now, simplify each term separately: - \(1^2 = 1\).- \(-2(1)(i) = -2i\).- \(i^2 = -1\) because \(i\) is the imaginary unit.
3Step 3: Combine the Terms
Substitute the simplified terms back into the expanded expression:\[ 1 - 2i + (-1) \] Combine like terms:\[ 1 - 1 - 2i = 0 - 2i \]
4Step 4: Write in the Form \(a + b i\)
The expression \(0 - 2i\) can be written in the form \(a + bi\) where \(a = 0\) and \(b = -2\). Hence: \[ (1-i)^2 = 0 - 2i \] or equivalently \[ -2i \].
Key Concepts
Imaginary UnitAlgebraic IdentitiesComplex Multiplication
Imaginary Unit
In the world of complex numbers, the imaginary unit is a crucial element. It is represented by the letter \(i\). The defining property of \(i\) is that \(i^2 = -1\). This means that the square of the imaginary unit results in a negative one, a concept not found in traditional, real numbers.
This fundamental rule allows complex numbers to be expressed in the form of \(a + bi\), where \(a\) and \(b\) are real numbers. Here, \(bi\) represents the imaginary part of the complex number.
This fundamental rule allows complex numbers to be expressed in the form of \(a + bi\), where \(a\) and \(b\) are real numbers. Here, \(bi\) represents the imaginary part of the complex number.
- Understanding \(i^2 = -1\) is key to simplifying expressions involving complex numbers.
- It allows us to find real and imaginary components when performing algebraic operations.
Algebraic Identities
Algebraic identities are powerful tools used to simplify and solve expressions, including those with complex numbers. One such identity is \((a-b)^2 = a^2 - 2ab + b^2\), which helps expand binomials.
In our example, \((1-i)^2\) uses this identity with \(a = 1\) and \(b = i\). This allows breaking down and simplifying the expression step by step.
In our example, \((1-i)^2\) uses this identity with \(a = 1\) and \(b = i\). This allows breaking down and simplifying the expression step by step.
- The identity helps us expand \((1-i)^2\) into components that are easier to handle.
- By plugging in \(a\) and \(b\) correctly, we use this formula to find each part: \(1^2\), \(-2 \cdot 1 \cdot i\), and \(i^2\).
Complex Multiplication
Complex multiplication is an essential operation involving complex numbers. The multiplication of complex numbers, such as \((1-i)^2\), involves both real and imaginary components, and it follows the distributive property.
In this case, we expand using an algebraic identity to handle the multiplication.
In this case, we expand using an algebraic identity to handle the multiplication.
- We first simplify by expanding the expression using \((a-b)^2\).
- We handle terms like \(-2i\) and \(i^2\) separately, utilizing the property of \(i^2 = -1\) to transform imaginary terms into real components when necessary.
- Finally, we combine like terms involving both real and imaginary components to write the result in the form \(a + bi\).
Other exercises in this chapter
Problem 53
Multiply. Then simplify if possible. Assume that all variables represent positive real numbers. $$ (2 \sqrt{x}-5)(3 \sqrt{x}+1) $$
View solution Problem 53
Simplify. Assume that all variables represent positive real numbers. $$ -\sqrt{32 a^{8} b^{7}} $$
View solution Problem 54
Rationalize each numerator. Assume that all variables represent positive real numbers. \(\sqrt{\frac{3}{7}}\)
View solution Problem 54
Simplify. Assume that the variables represent any real number. $$ \sqrt[4]{16 x^{4}} $$
View solution