Problem 53
Question
Multiply. Write all answers in the form \(a+b i.\) $$ 2 i(7-3 i) $$
Step-by-Step Solution
Verified Answer
The answer is \(6 + 14i\).
1Step 1: Distribute the Terms
To multiply the term outside the parentheses by each term inside, distribute the multiplication as follows: \[ 2i imes 7 + 2i imes (-3i) \]
2Step 2: Simplify Each Product
Calculate each product separately:1. \(2i imes 7 = 14i\)2. \(2i imes (-3i) = -6i^2 \)Recall that \( i^2 = -1 \), therefore, \(-6i^2 = 6\).
3Step 3: Combine Real and Imaginary Parts
Add the real and imaginary components from the simplified products:\[ 6 + 14i \]This is the answer in the form \( a + bi \).
Key Concepts
Multiplying Complex NumbersDistributive PropertyImaginary Unit
Multiplying Complex Numbers
Complex numbers can be a bit tricky at first, but with a bit of practice, you'll get the hang of it! Multiplying them might seem different from multiplying regular numbers, but it's quite straightforward when you break it down step by step. In the original exercise, you're asked to multiply
- 2i by the binomial expression (7 - 3i).
- a + bi, where a and b are real numbers.
Distributive Property
The distributive property is a cornerstone in algebra, and it applies to complex numbers just like it does for real numbers. Basically, it lets us distribute the multiplication of one number to each term inside a set of parentheses. It's like a magician spreading magic equally to everything in their hat!
In the original problem, we started with 2i (7 - 3i). To solve it, we multiplied 2i by each term within the parentheses:
In the original problem, we started with 2i (7 - 3i). To solve it, we multiplied 2i by each term within the parentheses:
- 2i * 7 yields 14i
- 2i * (-3i) gives us -6i2
-
a + bi makes it all add up perfectly!
Just remember this magical principle and you’ll be able to take on more complex challenges with confidence.
Imaginary Unit
The imaginary unit, denoted as i, is a fundamental part of complex numbers. It's what distinguishes them from real numbers. The special thing about i is that it represents the square root of -1. And, like magic, it follows the rule that i2 = -1. This characteristic is essential when you're working on multiplying complex numbers.
Going back to our example from the exercise, during Step 2, you ended up with a term -6i2.
Here’s where the trick with the imaginary unit comes into play!
Going back to our example from the exercise, during Step 2, you ended up with a term -6i2.
Here’s where the trick with the imaginary unit comes into play!
- Since i2 = -1, this means that -6i2 becomes 6.
- a + bi, yielding 6 + 14i.
Other exercises in this chapter
Problem 52
Simplify each expression. All variables represent positive real numbers. $$ \frac{\sqrt[3]{243 x^{8}}}{\sqrt[3]{9 x}} $$
View solution Problem 53
Simplify each expression. All variables represent positive real numbers. See Example 4. $$ \left(81 x^{4} y^{8}\right)^{3 / 4} $$
View solution Problem 53
Square or cube each quantity and simplify the result. $$ (\sqrt{3 x}+\sqrt{3})^{2} $$
View solution Problem 53
Simplify by combining like radicals. $$ 5 \sqrt{7}+3 \sqrt{7} $$
View solution