Problem 53
Question
Many software packages have programs for calculating limits, although you should be warned that they are not infallible. To develop confidence in your program, use it to recalculate some of the limits in Problems 1-28. Then for each of the following, find the limit or state that it does not exist. $$ \lim _{x \rightarrow 0} \cos (1 / x) $$
Step-by-Step Solution
Verified Answer
The limit does not exist because \(\cos(1/x)\) oscillates indefinitely as \(x\) approaches 0.
1Step 1: Understanding the problem
The problem asks us to find the limit of the function \( \cos(1/x) \) as \( x \) approaches 0. To solve this, we need to examine the behavior of the function as \( x \) gets closer to 0.
2Step 2: Analyzing the function
The function \( \cos(1/x) \) involves a trigonometric function applied to a reciprocal of \( x \). As \( x \rightarrow 0 \), the value of \( 1/x \) becomes very large, oscillating between positive and negative infinity.
3Step 3: Behavior of cosine function
Cosine is a periodic function with a period of \( 2\pi \), which oscillates between -1 and 1. As \( 1/x \) approaches positive or negative infinity, \( \cos(1/x) \) will continue to oscillate rapidly between these two bounds.
4Step 4: Conclusion on the limit
Due to the rapid oscillation of \( \cos(1/x) \) without settling to a particular value, the limit does not exist. The function does not approach any single value as \( x \rightarrow 0 \).
Key Concepts
Trigonometric FunctionsLimit BehaviorOscillation in Calculus
Trigonometric Functions
Trigonometric functions, like cosine, are vital in calculus. They are periodic and often repeat specific values across their intervals. For cosine, the function
- oscillates between -1 and 1,
- has a period of \(2\pi\).
Limit Behavior
Understanding limit behavior is a core part of calculus. Limits allow us to analyze what a function does as its input approaches a particular value. For a function \(f(x)\), the limit as \(x\) approaches a point \(a\) examines what value \(f(x)\) gets very close to as \(x\) nears \(a\).In this problem, as \(x\) approaches 0, the challenge is that the function \(\cos(1/x)\) does not slowly inch toward a number. Instead, its behavior is erratic. Therefore, a major takeaway here is recognizing when a limit might not exist due to such unpredictable nature.Not all trigonometric limits behave nicely. Some limits, like fractions involving polynomials, might simplify gradually to a point. But trig functions can misbehave greatly, especially when incorporating infinite elements, like \(1/x\). This is why the function \(\cos(1/x)\) fails to have a definable limit at 0 as it endlessly jumps around its bounded range.
Oscillation in Calculus
Oscillation refers to a function repeatedly changing between two states without settling into a point as an input approaches a given number. In calculus, this is especially significant in examining limits. For the function \(\cos(1/x)\), each time \(x\) gets smaller, \(1/x\) becomes larger in magnitude, causing the cosine to switch rapidly between its bounds, -1 and 1.
- This process is called oscillation, and
- Oscillation prevents the function from settling on a single limit.
Other exercises in this chapter
Problem 52
In Problems 49-54, determine the largest interval over which the given function is continuous. $$ f(x)=\operatorname{sech} x $$
View solution Problem 52
Using the symbols \(M\) and \(N\), give precise definitions of each expression. (a) \(\lim _{x \rightarrow \infty} f(x)=\infty\) (b) \(\lim _{x \rightarrow-\inf
View solution Problem 53
Give a rigorous proof that if \(\lim _{x \rightarrow \infty} f(x)=A\) and \(\lim _{x \rightarrow \infty} g(x)=B\), then $$ \lim _{x \rightarrow \infty}[f(x)+g(x
View solution Problem 54
Many software packages have programs for calculating limits, although you should be warned that they are not infallible. To develop confidence in your program,
View solution