Problem 53
Question
Keto \(-\) enol tautomerism is observed in : (a) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CHO}\) (b) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OCH}_{3}\) (c) \(\mathrm{C}_{6} \mathrm{H}_{3} \mathrm{COCH}_{2} \mathrm{COOH}\) (d) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COC}_{6} \mathrm{H}_{5}\)
Step-by-Step Solution
Verified Answer
The compound \(\mathrm{C}_{6} \mathrm{H}_{3} \mathrm{COCH}_{2} \mathrm{COOH}\) exhibits keto-enol tautomerism.
1Step 1: Understanding Keto-Enol Tautomerism
Keto-enol tautomerism occurs in compounds that have a hydrogen atom adjacent to a carbonyl group (known as alpha hydrogen). The compound must have this hydrogen and the ability to form a double bond between the carbonyl carbon and the adjacent carbon.
2Step 2: Analyzing Each Compound for Tautomerism
Let's look at each compound to see if they contain an alpha hydrogen that can participate in tautomerism:(a) \(\text{C}_{6}\text{H}_{5}\text{CHO}\) is an aldehyde with no alpha hydrogen, so no tautomerism.(b) \(\text{C}_{6}\text{H}_{5}\text{OCH}_{3}\) is an ether and lacks a carbonyl group, so no tautomerism.(c) \(\text{C}_{6}\text{H}_{3}\text{COCH}_{2}\text{COOH}\) has a keto group, carboxyl group, and hydrogens adjacent to the keto group indicative of the potential for tautomerism.(d) \(\text{C}_{6}\text{H}_{5}\text{COC}_{6}\text{H}_{5}\) is a ketone, but has no alpha hydrogen, thus cannot tautomerize.
3Step 3: Conclusion
The only compound that meets all the criteria for keto-enol tautomerism (presence of an alpha hydrogen next to a carbonyl group) is \(\text{C}_{6}\text{H}_{3}\text{COCH}_{2}\text{COOH}\). This compound can exhibit keto-enol tautomerism.
Key Concepts
Understanding Alpha HydrogenThe Role of the Carbonyl GroupTautomerism Analysis: Keto to Enol Transformation
Understanding Alpha Hydrogen
In organic chemistry, the term "alpha hydrogen" refers to a hydrogen atom that is situated next to a carbonyl group. This hydrogen plays a pivotal role in various chemical reactions, particularly in keto-enol tautomerism. The alpha hydrogen is bonded to the carbon atom adjacent to the carbonyl carbon. Here's why it's important:
- The presence of an alpha hydrogen is a prerequisite for the keto-enol tautomerism to occur. Without it, the transformation between the keto and enol forms cannot happen.
- In compounds where alpha hydrogens are present, these hydrogens can be acidic. This acidity allows them to be abstracted easily by a base, facilitating the conversion into an enolate intermediate.
The Role of the Carbonyl Group
A carbonyl group, characterized by a carbon atom double-bonded to an oxygen atom (503;O), is a common feature in many organic molecules. It's a defining component of various functional groups like ketones and aldehydes. Here's why the carbonyl group is crucial in tautomerism:
- The carbon-oxygen double bond is polarized, with oxygen being more electronegative than carbon. This polarity makes the carbon atom electrophilic, meaning it will seek to attract electrons.
- In the context of keto-enol tautomerism, the carbonyl group's electron-deficient nature facilitates the shift and redistribution of electrons, allowing the conversion to the enol form.
Tautomerism Analysis: Keto to Enol Transformation
Tautomerism analysis, particularly the transition from the keto form to the enol form, involves scrutinizing the structural changes in a molecule. Here's an overview of the process:
- Initiation Step: The process begins with the abstraction of an alpha hydrogen, leading to the formation of an enolate ion. This ion is a key intermediate in the mechanism.
- Electron Movement: The electrons from the enolate ion are redistributed to form a new double bond between the alpha carbon and the carbonyl carbon, while the carbon-oxygen double bond becomes a single bond.
- Enol Formation: The oxygen in the enol form gains a hydrogen, completing its transformation structure. Now, the former carbonyl oxygen is hydroxylated, resulting in the enol form where an alcohol group is adjacent to a double bond.
Other exercises in this chapter
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Maximum enol content is observed in (a) \(\mathrm{CH}_{3} \mathrm{COCH}_{2} \mathrm{COOC}_{2} \mathrm{H}_{5}\) (b) O=C1C=CC=CC1 (c) \(\mathrm{CH}_{3} \mathrm{CO
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Assign the IUPAC name to \(\left[\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CH}\right]_{3} \mathrm{COH}\). (a) 3 -( 2 -methylethyl)-3(1-methylethyl) pentan-2-ol (
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