Problem 53
Question
In Problems \(49-62, \mathbf{u}=\langle 2,-3\rangle, \mathbf{v}=\langle-1,5\rangle,\) and \(\mathbf{w}=\langle 3,-2\rangle .\) Find the indicated scalar or vector. $$ \mathbf{w} \cdot \mathbf{w} $$
Step-by-Step Solution
Verified Answer
The dot product \(\mathbf{w} \cdot \mathbf{w}\) is 13.
1Step 1: Understand the Dot Product
The dot product of two vectors \(\mathbf{a} = \langle a_1, a_2 \rangle\) and \(\mathbf{b} = \langle b_1, b_2 \rangle\) is given by the formula: \(\mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2b_2\). For a vector \(\mathbf{w} = \langle 3, -2 \rangle\), the dot product with itself is \(\mathbf{w} \cdot \mathbf{w} = 3 \times 3 + (-2) \times (-2)\).
2Step 2: Calculate the Dot Product for \(\mathbf{w} \cdot \mathbf{w}\)
Substitute the components of \(\mathbf{w}\) into the dot product formula: \( \mathbf{w} \cdot \mathbf{w} = 3 \times 3 + (-2) \times (-2) \). Calculate each term separately: \(3 \times 3 = 9\) and \((-2) \times (-2) = 4\).
3Step 3: Sum the products to find the result
Add the two products from Step 2: \( 9 + 4 = 13 \). Therefore, the dot product \(\mathbf{w} \cdot \mathbf{w}\) is 13.
Key Concepts
VectorsScalar MultiplicationVector Components
Vectors
Vectors are mathematical objects that have both a magnitude and a direction. Imagine an arrow where:
In our exercise, we have vectors like \( \mathbf{w} = \langle 3, -2 \rangle \), which are given in component form. This simply means that we describe the vector in terms of its horizontal and vertical movements.
Understanding vectors is essential because they allow us to model and solve real-world problems like navigation, forces, and speeds.
- The length of the arrow represents the magnitude.
- The direction in which the arrow points represents its direction.
In our exercise, we have vectors like \( \mathbf{w} = \langle 3, -2 \rangle \), which are given in component form. This simply means that we describe the vector in terms of its horizontal and vertical movements.
Understanding vectors is essential because they allow us to model and solve real-world problems like navigation, forces, and speeds.
Scalar Multiplication
Scalar multiplication involves multiplying a vector by a scalar, a real number that scales the vector's magnitude without changing its direction. Here's what happens:
This concept allows us to adjust vectors to represent larger or smaller quantities, making it incredibly useful in scaling movements or forces in physical simulations.
- The vector's size is multiplied by the scalar.
- Only its magnitude changes, not its direction (unless the scalar is negative, which also reverses the direction).
This concept allows us to adjust vectors to represent larger or smaller quantities, making it incredibly useful in scaling movements or forces in physical simulations.
Vector Components
Vector components are the building blocks of a vector. They represent the effect of a vector in each dimension independently, often referred to as the horizontal and vertical components, especially in two-dimensional space.
Understanding vector components allows you to resolve any vector into manageable parts, making complex problems more approachable and less overwhelming.
- The first component is along the x-axis (horizontal).
- The second component is along the y-axis (vertical).
Understanding vector components allows you to resolve any vector into manageable parts, making complex problems more approachable and less overwhelming.
Other exercises in this chapter
Problem 51
In Problems \(49-62, \mathbf{u}=\langle 2,-3\rangle, \mathbf{v}=\langle-1,5\rangle,\) and \(\mathbf{w}=\langle 3,-2\rangle .\) Find the indicated scalar or vect
View solution Problem 52
In Problems \(49-62, \mathbf{u}=\langle 2,-3\rangle, \mathbf{v}=\langle-1,5\rangle,\) and \(\mathbf{w}=\langle 3,-2\rangle .\) Find the indicated scalar or vect
View solution Problem 54
In Problems \(49-62, \mathbf{u}=\langle 2,-3\rangle, \mathbf{v}=\langle-1,5\rangle,\) and \(\mathbf{w}=\langle 3,-2\rangle .\) Find the indicated scalar or vect
View solution Problem 55
In Problems \(49-62, \mathbf{u}=\langle 2,-3\rangle, \mathbf{v}=\langle-1,5\rangle,\) and \(\mathbf{w}=\langle 3,-2\rangle .\) Find the indicated scalar or vect
View solution