Problem 53
Question
In \(48-55,\) if \(\log a=c,\) express each of the following in terms of \(c\) $$ \log \frac{a^{2}}{10} $$
Step-by-Step Solution
Verified Answer
The expression is \(2c - 1\).
1Step 1: Apply Logarithm Properties
Using the property of logarithms that states \( \log \frac{m}{n} = \log m - \log n \), we rewrite the expression \( \log \frac{a^2}{10} \) as \( \log a^2 - \log 10 \).
2Step 2: Expand Using Power Rule
Use the power rule for logarithms which states \( \log m^n = n \cdot \log m \) to expand \( \log a^2 \). This gives us \( 2 \log a \).
3Step 3: Substitute Known Values
Substitute \( \log a = c \) into the expression. So, \( 2 \log a \) becomes \( 2c \). Substitute this into the previous step: \( 2c - \log 10 \).
4Step 4: Substitute \(\log 10\) Value
We know that \( \log 10 = 1 \) because \( 10 \) is the base of the common logarithm. Substitute this into the expression to get \( 2c - 1 \).
Key Concepts
Logarithm PropertiesPower Rule for LogarithmsLogarithmic SubstitutionCommon Logarithm
Logarithm Properties
Logarithm properties serve as rules that help us manipulate and simplify logarithmic expressions. These properties make certain difficult calculations accessible by transforming complex logs into simpler forms. One crucial property is the quotient rule of logarithms, which allows us to handle division inside a log. If you have a logarithmic expression like \( \log \frac{m}{n} \), you can rewrite it using the rule:
- \( \log \frac{m}{n} = \log m - \log n \)
Power Rule for Logarithms
The power rule for logarithms is a powerful tool when you need to work with exponents inside a logarithmic expression. This rule states that if you have an expression like \( \log m^n \), you can simplify it to:
- \( \log m^n = n \cdot \log m \)
Logarithmic Substitution
Logarithmic substitution is a method used to simplify equations, especially when a particular logarithm is related to a known value. For example, if you know \( \log a = c \), substitution allows you to replace \( \log a \) with \( c \) in any given expression.
- When you see \( 2 \log a \), and you know \( \log a = c \), simply substitute to obtain \( 2c \).
Common Logarithm
The common logarithm, denoted as \( \log \), is a logarithm with base 10. It’s widely used due to its simplicity and because it's the base of the metric system. An essential aspect of the common logarithm is that \( \log 10 = 1 \). This is because raising 10 to the power of 1 results in 10.
- In any logarithmic expression, if you see \( \log 10 \), you can substitute it with 1, making calculations straightforward.
Other exercises in this chapter
Problem 52
In \(27-56,\) evaluate each logarithmic expression. Show all work. $$ \log _{\frac{1}{2}} \frac{1}{4} \cdot \log _{3} 81 \cdot \frac{1}{2} \log _{18} 324 $$
View solution Problem 53
In \(53-56,\) find each value of \(x\) to the nearest thousandth. $$ e^{x}=35 $$
View solution Problem 53
In \(27-56,\) evaluate each logarithmic expression. Show all work. $$ \frac{\log _{5} 25+2 \log _{10} 10}{\log _{16} 4} $$
View solution Problem 53
Solve each equation for the variable. \(\log _{2} 8+\log _{3} 9=\log _{b} 100,000\)
View solution