Problem 53
Question
Given that the following coordinates are the vertices of a rectangle, prove that this truly is a rectangle by showing the slopes of the sides that meet are perpendicular. (-1,1),(2,0),(3,3) and (0,4).
Step-by-Step Solution
Verified Answer
The sides AB and BC, as well as CD and DA, are perpendicular, confirming a rectangle.
1Step 1: Plot the Points
Visualize the problem by plotting the given points on a coordinate plane. The vertices are A(-1,1), B(2,0), C(3,3), and D(0,4). This will help in understanding the position of each point relative to each other.
2Step 2: Determine the Slope of AB
Calculate the slope of segment AB using the slope formula: \( m = \frac{y_2 - y_1}{x_2 - x_1} \). For points A(-1,1) and B(2,0):\[ m_{AB} = \frac{0 - 1}{2 - (-1)} = \frac{-1}{3} \]
3Step 3: Determine the Slope of BC
Calculate the slope of segment BC. For points B(2,0) and C(3,3):\[ m_{BC} = \frac{3 - 0}{3 - 2} = 3 \]
4Step 4: Check the Perpendicular Relationship of AB and BC
To prove the sides are perpendicular, the product of their slopes should be -1. For sides AB (-1/3) and BC (3), multiply the slopes:\[ m_{AB} \times m_{BC} = \frac{-1}{3} \times 3 = -1 \] Thus, AB and BC are perpendicular.
5Step 5: Determine the Slope of CD
Calculate the slope of segment CD. For points C(3,3) and D(0,4):\[ m_{CD} = \frac{4 - 3}{0 - 3} = -\frac{1}{3} \]
6Step 6: Determine the Slope of DA
Calculate the slope of segment DA. For points D(0,4) and A(-1,1):\[ m_{DA} = \frac{1 - 4}{-1 - 0} = 3 \]
7Step 7: Check the Perpendicular Relationship of CD and DA
Check if the product of slopes of CD and DA is -1:\[ m_{CD} \times m_{DA} = -\frac{1}{3} \times 3 = -1 \]Therefore, CD and DA are perpendicular.
Key Concepts
Slope of a LinePerpendicular LinesRectangle Properties
Slope of a Line
In analytic geometry, the slope of a line is a measure of the steepness or incline of the line. It tells us how much the line rises vertically for every unit it moves horizontally.
The slope is commonly represented by the letter "m" and is calculated using the formula:
The slope is commonly represented by the letter "m" and is calculated using the formula:
- \( m = \frac{y_2 - y_1}{x_2 - x_1} \)
- Difference in y-values = 0 - 1 = -1
- Difference in x-values = 2 - (-1) = 3
Perpendicular Lines
Perpendicular lines are an important concept in geometry. When two lines are perpendicular, they intersect at a right angle (90 degrees).
This right angle forms the basis for many geometric shapes and properties.The relationship between the slopes of two perpendicular lines is interesting. Two lines are perpendicular if the product of their slopes is -1.
This right angle forms the basis for many geometric shapes and properties.The relationship between the slopes of two perpendicular lines is interesting. Two lines are perpendicular if the product of their slopes is -1.
- If you have a line with a slope of \( m \), a perpendicular line will have a slope of \( -\frac{1}{m} \).
- Slope of AB: \( m_{AB} = \frac{-1}{3} \)
- Slope of BC: \( m_{BC} = 3 \)
Rectangle Properties
A rectangle is a four-sided polygon that has a few distinct properties, making it a special type of quadrilateral. Each corner of a rectangle forms a right angle.
This means all interior angles measure precisely 90 degrees.The most recognizable property of a rectangle is that opposite sides are equal and parallel. Another key feature is that two adjacent sides of a rectangle are perpendicular.In the given exercise, we determined the sides AB and BC to be perpendicular, forming a right angle. Similarly, sides CD and DA were shown to be perpendicular as well.
This means all interior angles measure precisely 90 degrees.The most recognizable property of a rectangle is that opposite sides are equal and parallel. Another key feature is that two adjacent sides of a rectangle are perpendicular.In the given exercise, we determined the sides AB and BC to be perpendicular, forming a right angle. Similarly, sides CD and DA were shown to be perpendicular as well.
- Slope of CD: \( m_{CD} = -\frac{1}{3} \)
- Slope of DA: \( m_{DA} = 3 \)
- Product: \( m_{CD} \times m_{DA} = -1 \)
Other exercises in this chapter
Problem 53
For the following exercises, evaluate the expressions, writing the result as a simplified complex number. $$ \frac{(3+i)^{2}}{(1+2 i)^{2}} $$
View solution Problem 53
For the following exercises, solve for the given variable in the formula. After obtaining a new version of the formula, you will use it to solve a question. The
View solution Problem 54
For the following exercises, input the left-hand side of the inequality as a \(Y 1\) graph in your graphing utility. Enter \(y 2=\) the right-hand side. Enterin
View solution Problem 54
A formula for the normal systolic blood pressure for a man age \(A,\) measured in \(\mathrm{mmHg}\), is given as \(P=0.006 A^{2}-0.02 A+120\) Find the age to th
View solution