Problem 53
Question
Given that the following coordinates are the vertices of a rectangle, prove that this truly is a rectangle by showing the slopes of the sides that meet are perpendicular. \((-1,1),(2,0),(3,3),\) and \((0,4)\)
Step-by-Step Solution
Verified Answer
The quadrilateral is a rectangle because its consecutive sides are perpendicular.
1Step 1: Plot the Points
First, let's plot the points \((-1,1), (2,0), (3,3),\) and \((0,4)\). Identify the possible sides. Use the coordinates to visualize the quadrilateral formed by these points.
2Step 2: Calculate Slopes of Sides
Calculate the slope of each side by selecting pairs of points: A = \((-1,1)\), B = \((2,0)\), C = \((3,3)\), and D = \((0,4)\).- For side AB: Use the formula \(m = \frac{y_2 - y_1}{x_2 - x_1}\). \[ m_{AB} = \frac{0 - 1}{2 - (-1)} = \frac{-1}{3} \]- For side BC: \[ m_{BC} = \frac{3 - 0}{3 - 2} = 3 \]- For side CD: \[ m_{CD} = \frac{4 - 3}{0 - 3} = \frac{1}{-3} = -\frac{1}{3} \]- For side DA: \[ m_{DA} = \frac{1 - 4}{-1 - 0} = \frac{-3}{-1} = 3 \]
3Step 3: Check Perpendicularity
To prove that the quadrilateral is a rectangle, opposite sides must be perpendicular. Two lines are perpendicular if the product of their slopes is -1.- Check if sides AB and BC are perpendicular: \[ m_{AB} \times m_{BC} = \left(-\frac{1}{3}\right) \times 3 = -1 \] Thus, AB is perpendicular to BC.- Check if sides CD and DA are perpendicular: \[ m_{CD} \times m_{DA} = \left(-\frac{1}{3}\right) \times 3 = -1 \] Thus, CD is perpendicular to DA.
4Step 4: Conclude It is a Rectangle
Since each pair of consecutive sides is perpendicular, the quadrilateral formed by the points is a rectangle. We verified perpendicularity using the calculated slopes.
Key Concepts
Coordinate GeometrySlope CalculationPerpendicular LinesQuadrilateral Properties
Coordinate Geometry
Coordinate geometry is a branch of geometry where we use a coordinate system to describe the positions of points or shapes in space. Here, the Cartesian coordinate system is used, allowing us to locate each vertex of a quadrilateral on a plane using pairs of numerical values called coordinates,
- The x-coordinate represents the horizontal position.
- The y-coordinate indicates the vertical position.
Slope Calculation
In coordinate geometry, slope calculation is a critical method used to determine the steepness or incline of a line connecting two points. The slope, denoted as \(m\), answers how much y changes with respect to x.The formula for calculating the slope between two points, \((x_1, y_1)\) and \((x_2, y_2)\), is: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
- For line AB connecting \((-1,1)\) and \((2,0)\): \[ m_{AB} = \frac{0 - 1}{2 - (-1)} = \frac{-1}{3} \]
- For line BC connecting \((2,0)\) and \((3,3)\): \[ m_{BC} = \frac{3 - 0}{3 - 2} = 3 \]
- For line CD connecting \((3,3)\) and \((0,4)\): \[ m_{CD} = \frac{4 - 3}{0 - 3} = -\frac{1}{3} \]
- For line DA connecting \((0,4)\) and \((-1,1)\): \[ m_{DA} = \frac{1 - 4}{-1 - 0} = 3 \]
Perpendicular Lines
Two lines are perpendicular if they intersect at a right angle (90 degrees). In coordinate geometry, we ascertain this by examining their slopes — specifically, the slopes of these two lines multiply to produce -1.In this exercise, the slopes of opposite sides were calculated:
- For lines AB and BC: \(m_{AB} = -\frac{1}{3}\), \(m_{BC} = 3\); and their product: \[ m_{AB} \times m_{BC} = -\frac{1}{3} \times 3 = -1 \]
- For lines CD and DA: \(m_{CD} = -\frac{1}{3}\), \(m_{DA} = 3\); and their product: \[ m_{CD} \times m_{DA} = -\frac{1}{3} \times 3 = -1 \]
Quadrilateral Properties
Quadrilaterals are four-sided polygons, with rectangles being a specific type. A key property of rectangles is that they have all right angles (90 degrees) between adjacent sides.
To confirm a quadrilateral is a rectangle using coordinate geometry, we demonstrate:
- Each pair of consecutive sides is perpendicular, as proven by their slopes multiplying to -1.
- The quadrilateral still must be closed, with points that connect into a four-sided shape without crossing over.
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