Problem 53
Question
(Gamma Function) Let \(\Gamma(n)=\int_{0}^{\infty} x^{n-1} e^{-x} d x, n>0 .\) This integral converges by Problems 51 and \(52 .\) Show each of the following (note that the gamma function is defined for every positive real number \(n\) ): (a) \(\Gamma(1)=1\) (b) \(\Gamma(n+1)=n \Gamma(n)\) (c) \(\Gamma(n+1)=n !\), if \(n\) is a positive integer.
Step-by-Step Solution
Verified Answer
(a) \(\Gamma(1) = 1\), (b) \(\Gamma(n+1) = n \Gamma(n)\), (c) \(\Gamma(n+1) = n!\) for positive integer \(n\).
1Step 1: Introduction to the Gamma Function
The Gamma function is an important function in mathematics which generalizes the factorial function to real and complex numbers. It is defined as \(\Gamma(n) = \int_{0}^{\infty} x^{n-1} e^{-x} \, dx\) for \(n > 0\). This exercise will demonstrate key properties of the Gamma function.
2Step 1: Evaluate \(\Gamma(1)\)
To find \(\Gamma(1)\), substitute \(n = 1\) into the definition: \(\Gamma(1) = \int_{0}^{\infty} x^{1-1} e^{-x} \, dx = \int_{0}^{\infty} e^{-x} \, dx\). The result of this integral is 1, since it represents the area under the curve of \(e^{-x}\) from 0 to \(\infty\). Thus, \(\Gamma(1) = 1\).
3Step 2: Prove Recursive Formula \(\Gamma(n+1) = n \Gamma(n)\)
Consider \(\Gamma(n+1) = \int_{0}^{\infty} x^n e^{-x} \, dx\). Use integration by parts where \(u = x^n\) and \(dv = e^{-x}dx\). This gives \(du = nx^{n-1}dx\) and \(v = -e^{-x}\). Applying integration by parts, we get \([ -x^n e^{-x} ]_0^{\infty} + \int_{0}^{\infty} nx^{n-1} e^{-x} \, dx\). The first term evaluates to 0, and the result of the integration by parts is \(n \Gamma(n)\). Thus, \(\Gamma(n+1) = n \Gamma(n)\).
4Step 3: Show \(\Gamma(n+1) = n!\) for Positive Integer \(n\)
Using the recursive formula proved in the previous step, \(\Gamma(n+1) = n \Gamma(n)\). Assume \(\Gamma(n) = (n-1)!\), which is true for \(\Gamma(1) = 0! = 1\). Applying the recursive formula repeatedly: \(\Gamma(2) = 1 \cdot \Gamma(1) = 1!\), \(\Gamma(3) = 2 \cdot \Gamma(2) = 2!\), and so on, results in \(\Gamma(n+1) = n!\). By mathematical induction, this holds for any positive integer \(n\).
Key Concepts
FactorialRecursive FormulaIntegration by Parts
Factorial
The concept of factorial is central to the Gamma function's properties. The factorial of a non-negative integer is the product of all positive integers less than or equal to that number. It is typically denoted as
- \(!n\) for a positive integer \(n\), calculated as \(n! = n \times (n-1) \times (n-2) \times ... \times 2 \times 1\).
- Special case: \(0!\) is defined to be 1.
- \(\Gamma(n+1)\) equals \(n!\), connecting the Gamma function to the factorial function.
- the factorial appears as a part of the expression \(\Gamma(n+1) = n!\) for integer \(n\).
Recursive Formula
Recursive formulas are equations that express a term in a sequence as a function of preceding terms. The Gamma function satisfies a very important recursive relation:
- \(\Gamma(n+1) = n \Gamma(n)\).
- If you know \(\Gamma(n)\), you can easily compute \(\Gamma(n+1)\) by multiplying \(\Gamma(n)\) by \(n\).
- For example: \(\Gamma(2) = 1 \cdot \Gamma(1)\), \(\Gamma(3) = 2 \cdot \Gamma(2)\), and so on.
Integration by Parts
Integration by parts is a fundamental technique in calculus used to integrate products of functions. It's applicable when one function can be easily differentiated and the other easily integrated. It is central to proving the recursive formula of the Gamma function. The rule is derived from the product rule for differentiation and is stated as follows:
- \(\int u \, dv = uv - \int v \, du\).
- Choose \(u = x^n\) and \(dv = e^{-x} \, dx\).
- Then, \(du = n x^{n-1} \, dx\) and \(v = -e^{-x}\).
- Evaluate the boundary terms at 0 and infinity, both vanishing to 0.
- Simplify the remaining integral to find it equals \(n \Gamma(n)\).
Other exercises in this chapter
Problem 48
Consider \(f(x)=n^{2} x e^{-n x}\). (a) Graph \(f(x)\) for \(n=1,2,3,4,5,6\) on \([0,1]\) in the same graph window. (b) For \(x>0\), find \(\lim _{n \rightarrow
View solution Problem 49
Find the absolute maximum and minimum points (if they exist) for \(f(x)=\left(x^{25}+x^{3}+2^{x}\right) e^{-x}\) on \([0, \infty)\).
View solution Problem 54
Evaluate \(\int_{0}^{\infty} x^{n-1} e^{-x} d x\) for \(n=1,2,3,4\), and 5, thereby confirming Problem \(53(\mathrm{c})\).
View solution Problem 57
By interpreting each of the following integrals as an area and then calculating this area by a \(y\) -integration, evaluate: (a) \(\int_{0}^{1} \sqrt{\frac{1-x}
View solution