Problem 53
Question
For the following problems, perform the divisions. $$ \frac{y^{3}+5 y^{2}-3}{y-1} $$
Step-by-Step Solution
Verified Answer
Answer: The quotient is $$y^2 + 6y + 6$$, and the remainder is $$3$$.
1Step 1: Setup the long division
Write the dividend, $$y^3 + 5y^2 - 3$$, inside the long division bracket and the divisor, $$y-1$$, outside of the bracket.
2Step 2: Divide the first term of the dividend by the first term of the divisor
Divide $$y^3$$ by $$y$$. The result is $$y^2$$, which will be the first term of our quotient.
3Step 3: Multiply the divisor by the result from Step 2
Multiply the divisor, $$y - 1$$, by $$y^2$$, which results in $$y^3 - y^2$$.
4Step 4: Subtract the result from Step 3 from the dividend
Subtract $$y^3 - y^2$$ from $$y^3 + 5y^2 - 3$$. The result is $$6y^2 - 3$$.
5Step 5: Repeat the division process with the new expression
Divide the first term of the new expression, $$6y^2$$, by the first term of the divisor, $$y$$. The result is $$6y$$, which is the next term of our quotient.
6Step 6: Multiply the divisor by the result from Step 5
Multiply the divisor, $$y - 1$$, by $$6y$$. The result is $$6y^2 - 6y$$.
7Step 7: Subtract the result from Step 6 from the new expression
Subtract $$6y^2 - 6y$$ from $$6y^2 - 3$$. The result is $$6y - 3$$.
8Step 8: Repeat the division process with the latest expression
Divide the first term of the new expression, $$6y$$, by the first term of the divisor, $$y$$. The result is $$6$$, which is the next term of our quotient.
9Step 9: Multiply the divisor by the result from Step 8
Multiply the divisor, $$y - 1$$, by $$6$$. The result is $$6y - 6$$.
10Step 10: Subtract the result from Step 9 from the latest expression
Subtract $$6y - 6$$ from $$6y - 3$$. The result is $$3$$, which is the remainder.
11Step 11: Write the final quotient and remainder
Our quotient from the long division is $$y^2 + 6y + 6$$, and our remainder is $$3$$. We can write the final answer as: $$
\frac{y^3 + 5y^2 - 3}{y - 1} = y^2 + 6y + 6 + \frac{3}{y - 1}
$$
Key Concepts
Understanding Long Division in PolynomialsInterpreting the RemainderQuotient: The Result of Division
Understanding Long Division in Polynomials
The process of long division you might remember from arithmetic works similarly with polynomials. When dividing polynomials, we aim to simplify a complex expression into a more manageable form. Here's how it unfolds, step by step:
- Set Up the Problem: In our exercise, we position the polynomial \(y^3 + 5y^2 - 3\) under the division bracket. This is known as the dividend. Outside the bracket, the polynomial \(y - 1\) is our divisor.
- Divide the First Terms: We start by dividing the leading term of the dividend, \(y^3\), by the leading term of the divisor, \(y\). This gives us \(y^2\), which is the first term in our quotient.
- Subtract and Repeat: After multiplying the divisor by \(y^2\), we subtract this from the dividend to get a new expression, then repeat the division process with this new expression until we reach a term we cannot divide the same way.
Interpreting the Remainder
In polynomial division, once the degree of the remaining polynomial is less than the degree of the divisor, we have what's known as the remainder. In our exercise, after a series of divisions and subtractions, we obtain a remainder of \(3\).
The remainder is crucial because it tells us about the closeness of the division. The smaller the remainder, the closer the division result is to being exact. In arithmetic terms, it's akin to the leftover in an integer division, that is, the amount that cannot be divided evenly.
Here's how the remainder fits into the final expression:
The remainder is crucial because it tells us about the closeness of the division. The smaller the remainder, the closer the division result is to being exact. In arithmetic terms, it's akin to the leftover in an integer division, that is, the amount that cannot be divided evenly.
Here's how the remainder fits into the final expression:
- The expression \(\frac{y^3 + 5y^2 - 3}{y - 1}\) can be rewritten with the remainder as \(y^2 + 6y + 6 + \frac{3}{y - 1}\).
- The quotient \(y^2 + 6y + 6\) represents the main part of the division, while \(\frac{3}{y - 1}\) accounts for the remainder.
Quotient: The Result of Division
The quotient in polynomial division represents the main result of the division process. As we simplified \(y^3 + 5y^2 - 3\) using the divisor \(y - 1\), each step contributed to building our quotient, \(y^2 + 6y + 6\).
- Building the Quotient: We achieved the quotient by continually dividing the leading terms of the polynomial and updating our expression step by step.
- Final Representation: The final represented form of the division is much simpler and easier to handle algebraically, expressed as \(y^2 + 6y + 6\).
Other exercises in this chapter
Problem 52
For the following problems, reduce each rational expression if possible. If not possible, state the answer in lowest terms. \(\frac{3 a+6}{3}\)
View solution Problem 53
For the following problems, perform the indicated operations. $$ \frac{7 a}{a+6}+\frac{5 a}{a-8} $$
View solution Problem 53
For the following problems, solve the rational equations. $$ \frac{2}{x^{2}}+\frac{3}{x}=2 $$
View solution Problem 53
For the following problems, perform the multiplications and divisions. $$ (a-2 b)^{4} \div \frac{(a-2 b)^{2}}{a+b} $$
View solution