Problem 53
Question
Factor by grouping. $$k t+3 k+8 t+24$$
Step-by-Step Solution
Verified Answer
The simplified expression after factoring by grouping is \((t + 3)(k + 8)\).
1Step 1: Group the terms
First, we need to group the terms that contain common factors. In our given expression, we can group the first two terms together and the last two terms together as follows:
\((k t + 3 k) + (8 t + 24)\)
2Step 2: Factor each group
Now, let's find the common factors of the grouped terms and factor them by dividing each term by the common factor.
\(k t + 3 k\) has a common factor of \(k\). So, let's take out \(k\) as a common factor:
\(k (t + 3)\)
\(8 t + 24\) has a common factor of \(8\). So, let's take out \(8\) as a common factor:
\(8 (t + 3)\)
Now, our expression looks like this:
\(k (t + 3) + 8 (t + 3)\)
3Step 3: Factor the common term
Finally, we can see that \((t + 3)\) is a common term in both parts of the expression. Let's factor it out:
\((t + 3) (k + 8)\)
Our factored expression is:
\((t + 3)(k + 8)\)
Key Concepts
Common FactorsAlgebraic ExpressionsFactoring Polynomials
Common Factors
In algebra, a common factor is a number or a variable that divides two or more algebraic terms without leaving a remainder. Recognizing common factors is essential when dealing with algebraic expressions, as it allows us to simplify the expression by pulling out the greatest common factor.
For example, in the expression \(kt + 3k\), both terms share a common factor of \(k\). Similarly, in the expression \(8t + 24\), the common factor is \(8\).
For example, in the expression \(kt + 3k\), both terms share a common factor of \(k\). Similarly, in the expression \(8t + 24\), the common factor is \(8\).
- The 'common factor' allows us to rewrite the expression in a more manageable form.
- It simplifies the polynomial and makes further manipulation possible.
- Identifying common factors is a crucial step in the process of factoring by grouping.
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and operations. They can represent a single value or a range of values, depending on the variables involved. Understanding how to manipulate these expressions is foundational in algebra.
In the context of factoring by grouping, we deal with expressions such as \(kt + 3k + 8t + 24\). This expression consists of four terms, each involving coefficients and variables.
In the context of factoring by grouping, we deal with expressions such as \(kt + 3k + 8t + 24\). This expression consists of four terms, each involving coefficients and variables.
- Each term in an algebraic expression can potentially have different properties that can be identified and manipulated.
- The ability to rearrange and group these terms is key for processes such as factoring by grouping.
- The structure of an expression influences how we approach techniques that simplify or solve it.
Factoring Polynomials
Factoring polynomials is the mathematical process of breaking down a polynomial into simpler 'factor' polynomials that can be multiplied together to give the original polynomial back. This is important in solving polynomial equations, simplifying expressions, and finding polynomial roots.
In factoring by grouping, we strategically group terms within a polynomial to reveal common factors. In the example \(kt + 3k + 8t + 24\), we initially group it as \((kt + 3k) + (8t + 24)\). Next, we factor out the common factors from each group: \(k(t + 3)\) and \(8(t + 3)\). Finally, noticing that \(t + 3\) appears in both, we can factor it out, resulting in \((t + 3)(k + 8)\).
In factoring by grouping, we strategically group terms within a polynomial to reveal common factors. In the example \(kt + 3k + 8t + 24\), we initially group it as \((kt + 3k) + (8t + 24)\). Next, we factor out the common factors from each group: \(k(t + 3)\) and \(8(t + 3)\). Finally, noticing that \(t + 3\) appears in both, we can factor it out, resulting in \((t + 3)(k + 8)\).
- Grouping helps identify patterns or structures within a polynomial that might not be immediately apparent.
- By systematically factoring each group, you ensure precision and avoid errors.
- Recognizing common factors in grouped terms facilitates the final factoring step, resulting in the simplified product of two binomials.
Other exercises in this chapter
Problem 52
Factor completely. Check your answer. $$u^{2}+2 u v-48 v^{2}$$
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Solve each equation. $$ 33=-m(14+m) $$
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Factor completely. Check your answer. $$c^{2}+6 c d-55 d^{2}$$
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Factor completely. $$9 a^{2}-1$$
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