Problem 53
Question
Evaluate the given integral by converting the integrand to an expression in sines and cosines. $$ \int \cot ^{3}(x / 3) \csc (x / 3) d x $$
Step-by-Step Solution
Verified Answer
\(-\csc^3(x/3) + 3\csc(x/3) + C\)
1Step 1: Express the cotangent and cosecant in terms of sine and cosine.
The cotangent and cosecant functions can be rewritten in terms of sine and cosine as follows:\[ \cot(u) = \frac{\cos(u)}{\sin(u)} \quad \text{and} \quad \csc(u) = \frac{1}{\sin(u)} \]Thus, the integrand \( \cot^{3}(x / 3) \csc(x / 3) \) becomes:\[ \left(\frac{\cos(x/3)}{\sin(x/3)}\right)^3 \cdot \frac{1}{\sin(x/3)} = \frac{\cos^{3}(x/3)}{\sin^{4}(x/3)} \]
2Step 2: Simplify the integrand using a trigonometric substitution.
Let \( u = \sin(x/3) \), then \( du = \frac{1}{3} \cos(x/3) \, dx \) which implies \( dx = 3 \frac{du}{\cos(x/3)} \). Substitute these into the integrand:\[ \int \frac{\cos^{3}(x/3)}{\sin^{4}(x/3)} \, dx = \int \frac{\cos(x/3)}{\sin^{4}(x/3)} \cdot \cos^2(x/3) \, dx \]
3Step 3: Use substitution to evaluate the integral in terms of u.
Substituting \( u = \sin(x/3) \) and rearranging, the integral becomes:\[ \int \frac{\cos^2(x/3)}{u^4} \, 3 \frac{du}{\cos(x/3)} = 3 \int \frac{\cos(x/3)}{u^4} \frac{\cos^2(x/3)}{\cos(x/3)} \, du = 3 \int \frac{\cos(x/3) \cdot \cos(x/3)}{u^4} \, du = 3 \int \frac{1 - u^2}{u^4} \, du \]
4Step 4: Simplify the integrand and integrate with respect to u.
Split \( \frac{1-u^2}{u^4} \) into two separate fractions:\[ \frac{1}{u^4} - \frac{u^2}{u^4} = \frac{1}{u^4} - \frac{1}{u^2} \]Integrate each term separately:\[ \int \frac{1}{u^4} \, du = \int u^{-4} \, du = \frac{u^{-3}}{-3} = -\frac{1}{3u^3} \]\[ \int \frac{1}{u^2} \, du = \int u^{-2} \, du = \frac{u^{-1}}{-1} = -\frac{1}{u} \]
5Step 5: Compile the results and back-substitute for x.
Combine the results from Step 4:\[ 3 \left( -\frac{1}{3u^3} + \frac{1}{u} \right) = -\frac{1}{u^3} + \frac{3}{u} \]Back-substitute \( u = \sin(x/3) \):\[ -\frac{1}{\sin^3(x/3)} + \frac{3}{\sin(x/3)} \]Thus, the evaluated integral is:\[ -\csc^3(x/3) + 3\csc(x/3) + C \]where \( C \) is the constant of integration.
Key Concepts
Trigonometric SubstitutionTrigonometric FunctionsIntegration Techniques
Trigonometric Substitution
Trigonometric substitution is a valuable technique used to simplify integrals, especially those involving trigonometric expressions in complex forms. In this problem, trigonometric substitution plays a crucial role in converting the integrand \[ \cot^{3}(x/3) \csc(x/3) \] into a form that's easier to integrate. This is achieved by expressing the trigonometric functions solely in terms of sine and cosine:
- The cotangent is expressed as \( \cot(u) = \frac{\cos(u)}{\sin(u)} \).
- The cosecant is expressed as \( \csc(u) = \frac{1}{\sin(u)} \).
Trigonometric Functions
Trigonometric functions are foundational in calculus and are pivotal for handling integrals involving angles. In this exercise, the primary functions used are:
- Sine (\( \sin \)): This function relates the length of the opposite side of a right triangle to its hypotenuse. It's crucial in the substitution \( u = \sin(x/3) \), a step that simplifies the integration.
- Cosine (\( \cos \)): This function provides the ratio of the adjacent side to the hypotenuse. It’s used to alter the expression into terms of sine and cosine, facilitating the integration.
- Cotangent (\( \cot \)): Defined as \( \cot(u) = \frac{\cos(u)}{\sin(u)} \), it changes into a pure fraction of sine and cosine, easing simplification.
- Cosecant (\( \csc \)): As the reciprocal of sine, \( \csc(u) = \frac{1}{\sin(u)} \), helps represent products of trigonometric functions as divisions of simple sines and cosines.
Integration Techniques
Integrating trigonometric expressions efficiently involves applying the right techniques. Here, the integral \[ \int \frac{\cos^{3}(x/3)}{\sin^{4}(x/3)} \, dx \] is tackled using known substitution methods. Key steps include:
- Transform the trigonometric expressions into simple sine and cosine terms.
- Use trigonometric substitution \( u = \sin(x/3) \) to express derivatives with simple expressions, converting a complicated integral into a manageable polynomial form.
- Split the integrand into separate integrable functions: \[ \frac{1-u^2}{u^4} \Rightarrow \frac{1}{u^4} - \frac{1}{u^2} \]
- Integrate each term individually: Techniques for integrating powers of \( u \) such as \[ \int u^{-4} \, du \text{ and } \int u^{-2} \, du \] are required, yielding antiderivatives like \[ -\frac{1}{3u^3} \text{ and } -\frac{1}{u} \].
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