Problem 53
Question
Estimating volume Estimate the volume of material in a cylindrical shell with length 30 in., radius 6 in., and shell thickness 0.5 in. (IMAGE CAN'T COPY)
Step-by-Step Solution
Verified Answer
The cylindrical shell's volume is approximately 541.65 cubic inches.
1Step 1: Understand the Cylindrical Shell
A cylindrical shell can be visualized as a hollow cylinder with specific inner and outer radii and a certain length. The thickness given is the difference between the outer radius and the inner radius.
2Step 2: Determine the Inner and Outer Radii
The radius given is the outer radius of the shell, which is 6 inches. The shell thickness is 0.5 inches. Thus, the inner radius is found by subtracting the thickness from the outer radius: \[5.5\, \text{inches} = 6\, \text{inches} - 0.5\, \text{inches}\]
3Step 3: Calculate Inner and Outer Volumes
The volume of a cylinder is calculated using the formula \( V = \pi r^2 h \). First, find the outer volume using the outer radius (6 in):\[V_{\text{outer}} = \pi (6^2)(30)\]Then find the inner volume using the inner radius (5.5 in):\[V_{\text{inner}} = \pi (5.5^2)(30)\]
4Step 4: Solve for Each Volume
Calculating the outer volume:\[V_{\text{outer}} = \pi (36)(30) = 1080\pi\, \text{cubic inches}\]Calculating the inner volume:\[V_{\text{inner}} = \pi (30.25)(30) = 907.5\pi\, \text{cubic inches}\]
5Step 5: Calculate the Volume of the Shell
Subtract the inner volume from the outer volume to find the volume of the shell:\[V_{\text{shell}} = V_{\text{outer}} - V_{\text{inner}} = 1080\pi - 907.5\pi = 172.5\pi\, \text{cubic inches}\]
6Step 6: Finalize the Calculation
To obtain the numerical value, multiply by \(\pi \approx 3.1416\):\[V_{\text{shell}} \approx 172.5 \times 3.1416 \approx 541.65\, \text{cubic inches}\]
Key Concepts
Volume of a CylinderOuter RadiusInner RadiusShell Thickness
Volume of a Cylinder
The volume of a cylinder is a measure of how much material or "stuff" fits inside. Think about it as fulling a cylindrical container with water or sand.
The formula is quite simple: \[V = \pi r^2 h\]
The formula is quite simple: \[V = \pi r^2 h\]
- **\(V\)** is the volume.
- **\(\pi\)** is a special number, approximately 3.1416.
- **\(r\)** is the radius of the cylinder's base.
- **\(h\)** is the height or length of the cylinder.
Outer Radius
The outer radius of a cylindrical shell is an essential component when calculating its volume. It's the distance from the center to the outer edge. This measure helps outline the entire boundary of the external surface of the shell.
In our example, the outer radius given is 6 inches. This means:
- Measure from the very center of the cylinder to one outer edge.
- Always consider the length of the cylinder, which, together with the radius, provides the surface area calculations needed for the volume.
Inner Radius
The inner radius is slightly different from the outer radius. It doesn't stretch to the outer edge of the shell but just within the start of the shell's material.
To calculate the inner radius:
- Start with the outer radius, here it is 6 inches.
- Subtract the shell's thickness, which is 0.5 inches.
- Thus, the inner radius is 5.5 inches.
Shell Thickness
Shell thickness can be visualized as the breadth of the wall that forms the cylindrical shell. Given in the example at 0.5 inches, shell thickness helps in defining:
- **The distinction between inner and outer volumes:** This difference enables you to see how much space the material occupies.
- **Structural integrity:** The thicker the shell, the more robust it usually is.
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Problem 53
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