Problem 53
Question
Combine like terms. $$2 a b+5 a b$$
Step-by-Step Solution
Verified Answer
The simplified expression is \(7ab\).
1Step 1: Identify Like Terms
Look at the expression given: \(2ab + 5ab\). Both terms contain the same variables 'a' and 'b' raised to the same powers, so they are like terms.
2Step 2: Combine Like Terms
Since both terms are like terms, we can add their coefficients together. The coefficients are the numbers in front of the variables: 2 and 5. Adding these gives us: \(2 + 5 = 7\).
3Step 3: Write the Simplified Expression
Now that we know the sum of the coefficients is 7, we write the simplified expression as \(7ab\).
Key Concepts
CoefficientsSimplifying ExpressionsLike Terms in Algebra
Coefficients
Let's start by demystifying what a coefficient is. In algebraic expressions, a coefficient is the number that is multiplied by a variable or a product of variables. Consider the term \(2ab\). Here, the number \(2\) is the coefficient.
It indicates that \(ab\) is being multiplied by \(2\). When we deal with like terms, the coefficients help us in determining how many sets of a particular variable-product we have.
For example, in the expression \(2ab + 5ab\), \(2\) and \(5\) are the coefficients, telling us the expression represents \(2\) lots of \(ab\) and \(5\) more lots of \(ab\).
When combining like terms, it's crucial to pay attention to these coefficients, as they determine the contribution each term makes to the total.
It indicates that \(ab\) is being multiplied by \(2\). When we deal with like terms, the coefficients help us in determining how many sets of a particular variable-product we have.
For example, in the expression \(2ab + 5ab\), \(2\) and \(5\) are the coefficients, telling us the expression represents \(2\) lots of \(ab\) and \(5\) more lots of \(ab\).
When combining like terms, it's crucial to pay attention to these coefficients, as they determine the contribution each term makes to the total.
Simplifying Expressions
Simplifying expressions is a fundamental skill in algebra that involves combining like terms, substituting in values, and using algebraic rules to make an expression easier to work with.
In our exercise, when given an expression like \(2ab + 5ab\), the goal of simplifying is to combine terms wherever possible. This process often makes it easier to understand, evaluate, or further manipulate the expression.
In our exercise, when given an expression like \(2ab + 5ab\), the goal of simplifying is to combine terms wherever possible. This process often makes it easier to understand, evaluate, or further manipulate the expression.
- Identify any like terms that can be combined, like we do with \(2ab\) and \(5ab\).
- Add or subtract the coefficients of these like terms.
- Rewrite the expression with the new simplified term, \(7ab\), in this case.
Like Terms in Algebra
An essential concept in algebra is recognizing like terms. Like terms are components of an expression that have the same variable parts. This means they have the same variable(s) raised to the same powers.
Take \(2ab\) and \(5ab\). They are like terms because both include the variables \(a\) and \(b\) to the same power. This is why we can combine them.
Here’s how you can identify and handle like terms:
Take \(2ab\) and \(5ab\). They are like terms because both include the variables \(a\) and \(b\) to the same power. This is why we can combine them.
Here’s how you can identify and handle like terms:
- Inspect the variables and their exponents in each term.
- If variables and exponents match, you've got like terms.
- Add or subtract their coefficients, as needed.
Other exercises in this chapter
Problem 53
Use a calculator to work. Approximate each of the following expressions to the nearest thousandth. $$\sqrt{12}+\sqrt{75}$$
View solution Problem 53
Find the value of each expression when \(x=-4\) $$-5 x+8$$
View solution Problem 53
For each pair of numbers, choose the number that is closest to 10. $$10.5 \text { and } 10.05$$
View solution Problem 53
What does multiplying a decimal number by 100 do to the decimal point?
View solution