Problem 53
Question
Bode's sequence Bode's sequence, defined by $$ a_{1}=0.4, \quad a_{k}=0.1\left(3 \cdot 2^{k-2}+4\right) \text { for } k \geq 2, $$ can be used to approximate distances of planets from the sun. These distances are measured in astronomical units, with \(1 \mathrm{AU}=93,000,000 \mathrm{mi}\). For example, the third term corresponds to Earth and the fifth term to the minor planet Ceres. Approximate the first five terms of the sequence.
Step-by-Step Solution
Verified Answer
The first five terms are 0.4, 0.7, 1.0, 1.6, 2.8.
1Step 1: Identify Initial Term
The first term of the sequence is given as \( a_1 = 0.4 \). This will form the base term from which subsequent terms will build.
2Step 2: Determine the Formula for Subsequent Terms
For \( k \geq 2 \), the terms of the sequence are generated by the formula \( a_k = 0.1(3 \cdot 2^{k-2} + 4) \). This formula will be used to calculate the terms \( a_2 \) through \( a_5 \).
3Step 3: Calculate the Second Term
Substitute \( k = 2 \) into the formula:\[ a_2 = 0.1(3 \cdot 2^{2-2} + 4) = 0.1(3 \cdot 1 + 4) = 0.1(7) = 0.7 \]
4Step 4: Calculate the Third Term
Substitute \( k = 3 \) into the formula:\[ a_3 = 0.1(3 \cdot 2^{3-2} + 4) = 0.1(3 \cdot 2 + 4) = 0.1(10) = 1.0 \]
5Step 5: Calculate the Fourth Term
Substitute \( k = 4 \) into the formula:\[ a_4 = 0.1(3 \cdot 2^{4-2} + 4) = 0.1(3 \cdot 4 + 4) = 0.1(16) = 1.6 \]
6Step 6: Calculate the Fifth Term
Substitute \( k = 5 \) into the formula:\[ a_5 = 0.1(3 \cdot 2^{5-2} + 4) = 0.1(3 \cdot 8 + 4) = 0.1(28) = 2.8 \]
7Step 7: Conclusion: Listing the First Five Terms
The first five terms of Bode's sequence are \( a_1 = 0.4 \), \( a_2 = 0.7 \), \( a_3 = 1.0 \), \( a_4 = 1.6 \), and \( a_5 = 2.8 \).
Key Concepts
Astronomical UnitsPlanetary DistancesSequence Calculation
Astronomical Units
Astronomical Units (AU) are a standard unit of measurement used to describe distances within our solar system. One Astronomical Unit is equivalent to the average distance between the Earth and the Sun, which is approximately 93 million miles or about 149.6 million kilometers. This measurement provides a simple way to express and compare distances between planets and other celestial objects without dealing with huge numbers.
Understanding the concept of AU is crucial when learning about planetary distances and models like Bode's sequence that approximate these distances. Here are a few facts about astronomical units:
- 1 AU is the average distance from the Earth to the Sun.
- It simplifies the representation of distances within the solar system.
- It provides a bridge between smaller units like kilometers and the vast expanses of space.
- This unit is widely used in astronomy to discuss planetary orbits and celestial bodies.
Planetary Distances
Understanding planetary distances is essential for exploring our solar system and beyond. Distances between planets can vary based on their orbits, but Bode's sequence provides a rough estimation. In the context of Bode's sequence, each term gives an approximate distance in Astronomical Units from the Sun. This sequence presents a pattern that reflects the spacing of planetary orbits.
Planetary distances are typically calculated in terms of AU to maintain clarity and consistency. With Bode's rule:
- The first term corresponds to the innermost object, Mercury.
- Following terms represent planets like Earth, Mars, and the asteroid belt (e.g., Ceres).
- This simplification helps in determining relative distances easily.
- Understanding these distances can aid in visualizing the solar system's vastness.
Sequence Calculation
Sequence calculation involves deriving terms based on a mathematical formula. Bode's sequence offers an interesting method to approximate planetary distances by defining each term through calculations. In general terms:
- The sequence starts with a given first term, such as 0.4 AU for Mercury.
- Each subsequent term is calculated using a specific formula: \( a_k = 0.1(3 \cdot 2^{k-2} + 4) \).
- This formula involves exponential growth with factors of 2 and arithmetic adjustments (adding 4 then multiplying by 0.1).
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