Problem 53
Question
Add or subtract the rational expressions as indicated. Be sure to express your answers in simplest form. $$ \frac{-3}{4 n+5}-\frac{8}{3 n+5} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \( \frac{-41n - 55}{(4n+5)(3n+5)} \).
1Step 1: Identify the denominators
In the expression \( \frac{-3}{4n+5} - \frac{8}{3n+5} \), we have two denominators: \( 4n+5 \) and \( 3n+5 \). To subtract these rational expressions, we need a common denominator.
2Step 2: Find the least common denominator (LCD)
The least common denominator of \( 4n+5 \) and \( 3n+5 \) is their product \((4n+5)(3n+5)\) because they do not have common factors.
3Step 3: Adjust each fraction to have the LCD
Rewrite each fraction with the common denominator \((4n+5)(3n+5)\):- Multiply the numerator and denominator of the first fraction by \((3n+5)\) to get \( \frac{-3(3n+5)}{(4n+5)(3n+5)} \).- Multiply the numerator and denominator of the second fraction by \((4n+5)\) to get \( \frac{8(4n+5)}{(4n+5)(3n+5)} \).
4Step 4: Rewrite the expression with a common denominator
Now the expression becomes:\[ \frac{-3(3n+5)}{(4n+5)(3n+5)} - \frac{8(4n+5)}{(4n+5)(3n+5)} \].
5Step 5: Subtract the numerators
Subtract the numerators:\[ -3(3n+5) - 8(4n+5) \].Distribute to get:\[ -9n-15 - 32n-40 \].Combine like terms:\[ -9n - 32n - 15 - 40 = -41n - 55 \].
6Step 6: Write the final expression
The final expression is:\[ \frac{-41n-55}{(4n+5)(3n+5)} \].Since there are no common factors between \(-41n-55\) and \((4n+5)(3n+5)\), the expression is in its simplest form.
Key Concepts
Understanding the Least Common DenominatorMastering Subtracting FractionsSimplifying Expressions Fully
Understanding the Least Common Denominator
Rational expressions often require us to work with different denominators. To effectively add or subtract them, we must find a common denominator. This is called the Least Common Denominator (LCD). It is the smallest expression that can be evenly divided by each of the denominators involved in the expressions we are dealing with. In our example, the denominators are \(4n+5\) and \(3n+5\). Because they share no common factors, the LCD is simply their product: \((4n+5)(3n+5)\). This ensures that both fractions can be expressed in terms of the same denominator, which allows us to subtract them seamlessly. To find an LCD, follow these tips:
- List the factors of each denominator.
- Identify any common factors.
- Multiply the unique factors together.
Mastering Subtracting Fractions
Once you have a common denominator, subtracting fractions is similar to working with the numerical fractions you learned early on in math. With rational expressions, the only difference is the presence of variables. In our exercise, both fractions \( \frac{-3(3n+5)}{(4n+5)(3n+5)} \) and \( \frac{8(4n+5)}{(4n+5)(3n+5)} \) have the same denominator, simplifying the subtraction process. Here's a step-by-step method:
- Keep the denominator the same.
- Subtract the numerators by distributing first: \(-3(3n+5) - 8(4n+5)\).
- Distribute inside the parentheses to simplify each term.
- Combine like terms to form a single expression.
Simplifying Expressions Fully
Simplification is the final, and quite satisfying, step when working with rational expressions. In this process, the goal is to reduce the expression to its simplest form. This involves further combining like terms or factoring. For our problem, the subtraction resulted in the numerator \(-41n-55\), and the denominator remained \((4n+5)(3n+5)\). Here’s how you can approach simplification:
- Look for common factors in the numerator and denominator.
- If there are any common factors, divide them out to simplify.
- If there are no common factors, as in our case, the expression is already simplified.
Other exercises in this chapter
Problem 53
For problems \(53-64\), use synthetic division to determine the quotient and remainder. $$ \left(x^{2}-8 x+12\right) \div(x-2) $$
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Simplify each complex fraction. $$ \frac{3+\frac{2}{n+4}}{5-\frac{1}{n+4}} $$
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Give a step-by-step description of how to do the following multiplication problem. $$ \frac{x^{2}+5 x+6}{x^{2}-2 x-8} \cdot \frac{x^{2}-16}{16-x^{2}} $$
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For Problems 51-58, simplify each rational expression. You will need to use factoring by grouping. \(\frac{a x-3 x+2 a y-6 y}{2 a x-6 x+a y-3 y}\)
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