Problem 53
Question
A real zero of the numerator of a rational function \(f\) is \(x=c .\) Must \(x=c\) also be a zero of \(f ?\) Explain.
Step-by-Step Solution
Verified Answer
Yes, if \(x = c\) is a zero of the numerator of a rational function \(f\), then it must also be a zero of \(f\), provided that \(c\) is not a zero of the denominator.
1Step 1 – Understanding Rational Functions
Recall that a rational function is defined as \(f(x) = \frac{P(x)}{Q(x)}\), where \(P(x)\) and \(Q(x)\) are polynomial functions. The zero(s) of \(P(x)\), or the numerator, occur at the values of \(x\) for which \(P(x) = 0\). Similarly, the zero(s) of \(Q(x)\), or the denominator, occur at the values of \(x\) for which \(Q(x) = 0\).
2Step 2 – Considering Zeros of the Numerator
If \(x = c\) is a zero of \(P(x)\), that means \(P(c) = 0\). Substituting into the rational function yields \(f(c) = \frac{P(c)}{Q(c)} = \frac{0}{Q(c)}\).
3Step 3 – Analyzing the Result
From the above, it can be seen that the function \(f(x)\) at \(x = c\) will be zero provided that \(Q(c)\) is not equal to zero. Because division by zero is undefined, it is important that we establish \(Q(c) \neq 0\). If this is the case, then \(f(c)\) is indeed zero. So, if \(x = c\) is a zero of the numerator of the function, then it is also a zero of \(f\), provided that \(c\) is not a zero of the denominator.
Key Concepts
PolynomialsNumerator and DenominatorZeros of Functions
Polynomials
Polynomials are a fundamental concept in algebra. They are expressions composed of variables and coefficients, constructed using only the operations of addition, subtraction, multiplication, and non-negative integer exponents. A standard polynomial is expressed in the form:
\[ P(x) = a_n x^n + a_{n-1} x^{n-1} + \ldots + a_1 x + a_0 \] where \(a_n\), \(a_{n-1}\), ..., \(a_0\) are coefficients, and \(n\) is a non-negative integer representing the degree of the polynomial. The degree is determined by the highest power of \(x\).
\[ P(x) = a_n x^n + a_{n-1} x^{n-1} + \ldots + a_1 x + a_0 \] where \(a_n\), \(a_{n-1}\), ..., \(a_0\) are coefficients, and \(n\) is a non-negative integer representing the degree of the polynomial. The degree is determined by the highest power of \(x\).
- Polynomials can model various curves and can be used in equations to determine relationships between variables.
- The zeros of a polynomial are the values of \(x\) that satisfy \(P(x) = 0\). These zeros are critical in graphing and analyzing functions.
Numerator and Denominator
In the realm of rational functions, you frequently encounter the terms "numerator" and "denominator." A rational function is expressed as the ratio of two polynomials:
\[ f(x) = \frac{P(x)}{Q(x)} \] where \(P(x)\) is the numerator and \(Q(x)\) is the denominator. These components determine the behavior and properties of the rational function.
\[ f(x) = \frac{P(x)}{Q(x)} \] where \(P(x)\) is the numerator and \(Q(x)\) is the denominator. These components determine the behavior and properties of the rational function.
- The numerator, \(P(x)\), influences the zeros of the rational function. When \(P(x) = 0\), the rational function will be zero, provided the denominator is not zero at that point.
- The denominator, \(Q(x)\), plays a crucial role in the definition of the function, particularly for determining points of undefined values. If \(Q(x) = 0\), the rational function at that specific \(x\)-value is undefined, leading to vertical asymptotes or holes in its graph.
Zeros of Functions
Understanding the zeros of functions is essential in identifying where a function crosses the x-axis in a graph. For a rational function \(f(x) = \frac{P(x)}{Q(x)}\), the zeros are determined by solving \(P(x) = 0\) while ensuring that \(Q(x) eq 0\).
- Zeros of the Numerator: If \(x = c\) is a zero of the numerator \(P(x)\), it means that \(P(c) = 0\). The function value \(f(c)\) will equal zero only if \(Q(c) eq 0\). Otherwise, if \(Q(c) = 0\), \(f(c)\) would be undefined, as division by zero is impossible.
- Zeros of the Denominator: When \(Q(x) = 0\), the rational function is not defined at that value of \(x\). This leads to vertical asymptotes or holes, thus impacting the continuity of the graph.
Other exercises in this chapter
Problem 52
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