Problem 53
Question
A reaction has the following experimental rate equation: Rate \(=k[\mathrm{A}]^{2}[\mathrm{B}] .\) If the concentration of \(\mathrm{A}\) is doubled and the concentration of B is halved, what happens to the reaction rate?
Step-by-Step Solution
Verified Answer
The reaction rate doubles.
1Step 1: Understand the Rate Law
The rate law for the reaction is given by: \( \text{Rate} = k[\mathrm{A}]^{2}[\mathrm{B}] \). This means the reaction rate is proportional to the square of the concentration of \( \mathrm{A} \) and directly proportional to the concentration of \( \mathrm{B} \). \( k \) is the rate constant.
2Step 2: Determine the Effect of Doubling \( \mathrm{A} \)
If the concentration of \( \mathrm{A} \) is doubled, it goes from \( \mathrm{A} \) to \( 2\mathrm{A} \). Since the rate law involves \( [\mathrm{A}]^2 \), you substitute \( 2\mathrm{A} \) for \( \mathrm{A} \): \( (2[\mathrm{A}])^2 = 4[\mathrm{A}]^2 \). Thus, this change increases the rate by a factor of 4.
3Step 3: Determine the Effect of Halving \( \mathrm{B} \)
If \( \mathrm{B} \) concentration is halved, it changes from \( [\mathrm{B}] \) to \( \frac{1}{2}[\mathrm{B}] \). Substituting this into the rate equation, the effect of \([\mathrm{B}] \) becomes \( \frac{1}{2}[\mathrm{B}] \). Thus, this change decreases the rate by a factor of \( \frac{1}{2} \).
4Step 4: Combine Effects of Both Changes
Now, combine both effects: \( 4[\mathrm{A}]^2 \) from doubling \( \mathrm{A} \) and \( \frac{1}{2}[\mathrm{B}] \) from halving \( \mathrm{B} \). The overall rate change is \( 4 \times \frac{1}{2} = 2 \).
5Step 5: Conclude the Result
The final reaction rate increases by a factor of 2, which means it doubles when \( \mathrm{A} \) is doubled and \( \mathrm{B} \) is halved.
Key Concepts
Rate ConstantConcentration ChangesProportional Relationships
Rate Constant
The rate constant, often denoted as \( k \), is a fundamental part of the rate equation. It links the reaction rate with the concentrations of reactants raised to specific powers. Despite changes in concentration, \( k \) remains unchanged. This property makes it essential in determining how quickly a reaction progresses under given conditions.
Every reaction has its own specific rate constant at a particular temperature, and it's determined experimentally. In the reaction \( ext{Rate} = k[ ext{A}]^2[ ext{B}] \), \( k \) demonstrates the inherent speed of the reaction. Remember:
Every reaction has its own specific rate constant at a particular temperature, and it's determined experimentally. In the reaction \( ext{Rate} = k[ ext{A}]^2[ ext{B}] \), \( k \) demonstrates the inherent speed of the reaction. Remember:
- \( k \) is determined by characteristics of the reaction itself, such as the types of reactants and the temperature.
- It does not change with concentration changes of reactants.
- Units of \( k \) vary depending on the overall order of the reaction, making it crucial to understand dimensionality in kinetics.
Concentration Changes
Changes in concentration of reactants directly affect the reaction rate in accordance with the reaction's rate law. In our example rate law \( ext{Rate} = k[ ext{A}]^2[ ext{B}] \), the reaction rate is influenced by changes in concentrations of \( ext{A} \) and \( ext{B} \). This showcases how different orders of reactions affect the contribution of each reactant to the reaction rate:
- Doubling \( ext{A} \) has a squared effect because it is raised to the power of 2, showing a greater sensitivity to its concentration change.
- Halving \( ext{B} \) results in the rate being multiplied by \( \frac{1}{2} \), exhibiting a direct and proportional effect since it is raised to the first power.
Proportional Relationships
The principle of proportional relationships in reaction kinetics is a cornerstone concept. When examining the rate law \( ext{Rate} = k[ ext{A}]^2[ ext{B}] \), it becomes clear how the relationship between concentration and rate directly influences how the reaction behaves.
Key aspects include:
Key aspects include:
- The reaction rate is proportional to \( [ ext{A}]^2 \), meaning every change in the concentration of \( ext{A} \) drastically affects the reaction since the change is squared.
- For \( [ ext{B}] \), the reaction rate is linearly proportional. A simple change in its concentration results in a directly proportional change in the rate.
- Understanding these relationships enables prediction of outcomes when reactants are added or removed in varying quantities.
Other exercises in this chapter
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