Problem 53
Question
A proposed mechanism for the reaction of \(\mathrm{NO}_{2}\) and \(\mathrm{CO}\) is Step 1 Slow, endothermic $$2 \mathrm{NO}_{2}(\mathrm{g}) \longrightarrow \mathrm{NO}(\mathrm{g})+\mathrm{NO}_{3}(\mathrm{g})$$ Step 2 \(\quad\) Fast, exothermic $$\mathrm{NO}_{3}(\mathrm{g})+\mathrm{CO}(\mathrm{g}) \longrightarrow \mathrm{NO}_{2}(\mathrm{g})+\mathrm{CO}_{2}(\mathrm{g})$$ Overall Reaction Exothermic $$\mathrm{NO}_{2}(\mathrm{g})+\mathrm{CO}(\mathrm{g}) \longrightarrow \mathrm{NO}(\mathrm{g})+\mathrm{CO}_{2}(\mathrm{g})$$ (a) Identify each of the following as a reactant, product, or intermediate: \(\mathrm{NO}_{2}(\mathrm{g}), \mathrm{CO}(\mathrm{g}), \mathrm{NO}_{3}(\mathrm{g}), \mathrm{CO}_{2}(\mathrm{g})\) \(\mathrm{NO}(\mathrm{g})\) (b) Draw a reaction coordinate diagram for this reaction. Indicate on this drawing the activation energy for each step and the overall reaction enthalpy.
Step-by-Step Solution
VerifiedKey Concepts
Reactants and Products
**Products**, however, are what you get at the end of a reaction. In this scenario, after the reaction has occurred, you end up with nitrogen monoxide (\(\mathrm{NO}\)) and carbon dioxide (\(\mathrm{CO}_2\)). These are the substances formed as the reaction concludes.
To sum up, in the overall reaction:
- Reactants: \(\mathrm{NO}_2(\mathrm{g})\) and \(\mathrm{CO}(\mathrm{g})\) - Products: \(\mathrm{NO}(\mathrm{g})\) and \(\mathrm{CO}_2(\mathrm{g})\)
Reaction Intermediates
In the example of the \(\mathrm{NO}_2\) and \(\mathrm{CO}\) reaction, nitrogen trioxide (\(\mathrm{NO}_3\)) acts as an intermediate. It appears during the process but does not appear in the final equation. Since \(\mathrm{NO}_3\) is used up in the process, you won't see it in the end products. It's there to help along the way, speeding up or facilitating certain steps in the transition from initial to final state.
Also, in this mechanism, \(\mathrm{NO}\) is generated in the first step and then used up, fitting the description of an intermediate, even though it's also a product. Locale often changes perception!
Reaction Coordinate Diagram
For our \(\mathrm{NO}_2\) and \(\mathrm{CO}\) reaction, the diagram will show two significant peaks: one for each step in the mechanism. The height of each peak indicates the energy required to pass through that step.
Here’s a quick rundown of what the diagram looks like: - Start high on the energy axis because the first step is endothermic (absorbing energy). - The first peak represents the energy barrier for the first, slow step and is higher due to its increased energy input. - After that peak, the reaction lowers slightly for the intermediates. - The second peak is smaller because the exothermic part releases energy quickly. This part slopes back down, reflecting the lower energies of the final products compared to the starting materials.
Activation Energy
In our reaction mechanism, the first step is slow, indicating it has a higher activation energy. The endothermic nature of the step means there's more energy to overcome, represented as a taller peak in the reaction coordinate diagram for this slow step.
On the other hand, the fast second step requires less activation energy, because it is aided by the energy release when molecules transform, so it's depicted as a shorter peak.
Understanding activation energy is key to controlling reaction rates. You could speed up a reaction by lowering this barrier, perhaps using a catalyst to do so without changing the initial and final energy states!
Enthalpy Change
In this chemical mechanism, despite the first step being endothermic, the overall reaction is exothermic. This means more energy is released in forming the products than is needed to break the bonds of the reactants. The entire reaction ends at a lower energy level than it began, releasing heat into the environment.
Differentiating steps, the **overall enthalpy change** arises from comparing the initial energy level of the reactants with the final energy level of the products. This tells us that in a completed reaction, most of the heat flows out, particularly noticeable in the creation of \(\mathrm{CO}_2\). Understanding this balance helps in predicting how favorably a reaction will proceed under given conditions.