Problem 527
Question
Find the exact solution for \(5 e^{3 x}-4=6 .\) If there is no solution, write no solution.
Step-by-Step Solution
Verified Answer
The exact solution is \(x = \frac{\ln(2)}{3}\).
1Step 1: Isolate the Exponential Term
Start with the equation: \[ 5e^{3x} - 4 = 6 \] Add 4 to both sides to isolate the exponential expression:\[ 5e^{3x} = 10 \]
2Step 2: Solve for the Exponent
Divide both sides by 5 to further isolate the exponential term:\[ e^{3x} = 2 \]
3Step 3: Apply the Natural Logarithm
Take the natural logarithm (ln) of both sides to solve for the exponent:\[ \ln(e^{3x}) = \ln(2) \]Since \( \ln(e^{y}) = y \); therefore,\[ 3x = \ln(2) \]
4Step 4: Solve for x
Divide both sides by 3 to solve for \( x \):\[ x = \frac{\ln(2)}{3} \]
5Step 5: Final Calculation
Use a calculator to find the value of \( \ln(2) \) if necessary for further evaluation, or leave as it is for an exact solution. The solution is:\[ x \approx 0.231 \] using the approximation for \( \ln(2) \) calculated as approximately 0.693.
Key Concepts
Natural LogarithmSolving EquationsExact Solutions
Natural Logarithm
The natural logarithm, often denoted as ln, is a mathematical function that is used to transform exponential functions into linear ones, making them easier to solve. It is the inverse operation of the exponential function with base e, where e is approximately 2.718.
Understanding the natural logarithm is crucial when dealing with exponential equations since it allows us to isolate and solve for the exponent in the equation. For example, in the equation \( e^{3x} = 2 \), applying the natural logarithm to both sides gives \( \ln(e^{3x}) = \ln(2) \). This step is particularly important because it transforms the power of e, the base, into a more manageable linear form, \( 3x = \ln(2) \).
Some key properties to remember about the natural logarithm include:
Understanding the natural logarithm is crucial when dealing with exponential equations since it allows us to isolate and solve for the exponent in the equation. For example, in the equation \( e^{3x} = 2 \), applying the natural logarithm to both sides gives \( \ln(e^{3x}) = \ln(2) \). This step is particularly important because it transforms the power of e, the base, into a more manageable linear form, \( 3x = \ln(2) \).
Some key properties to remember about the natural logarithm include:
- \( \ln(e^x) = x \)
- \( \ln(1) = 0 \)
- \( \ln(ab) = \ln(a) + \ln(b) \)
Solving Equations
Solving equations involves finding the value of unknown variables that make the equation true. When dealing with exponential equations, like \(5 e^{3 x} - 4 = 6\), it’s essential to understand how to systematically isolate the variable to unveil the solution.
The first step typically involves isolating the term with the exponent. For instance, adding 4 to both sides of the initial equation \(5 e^{3x} - 4 = 6\) results in \(5 e^{3x} = 10\), which simplifies the problem and gets it closer to a solvable form.
Next, divide through by the coefficient of the exponential expression. In this example, dividing both sides by 5 gives \(e^{3x} = 2\). The equation is now in a form where taking the natural logarithm is the logical next step.
The first step typically involves isolating the term with the exponent. For instance, adding 4 to both sides of the initial equation \(5 e^{3x} - 4 = 6\) results in \(5 e^{3x} = 10\), which simplifies the problem and gets it closer to a solvable form.
Next, divide through by the coefficient of the exponential expression. In this example, dividing both sides by 5 gives \(e^{3x} = 2\). The equation is now in a form where taking the natural logarithm is the logical next step.
- Isolate the exponential or variable term
- Use inverse operations like division or square root where applicable
- Finally, apply logarithms to handle exponential terms effectively
Exact Solutions
An exact solution refers to the precise mathematical answer to a given equation without approximations. In exercises involving exponential equations, obtaining an exact solution often implies leaving the answer in logarithmic form rather than a decimal or rounded approximation.
For the equation we solved, \( x = \frac{\ln(2)}{3} \) is the exact solution. This form represents the exact numerical value of x without converting the natural logarithm to its decimal equivalent, allowing it to remain in its pure mathematical state.
Exact solutions are particularly valuable in theoretical mathematics and when further symbolic calculations are needed, as they offer the utmost precision. When decimal values are necessary, approximation can be used as in \( x \approx 0.231 \), but this represents an approximate solution derived from \( \ln(2) \approx 0.693 \).
For the equation we solved, \( x = \frac{\ln(2)}{3} \) is the exact solution. This form represents the exact numerical value of x without converting the natural logarithm to its decimal equivalent, allowing it to remain in its pure mathematical state.
Exact solutions are particularly valuable in theoretical mathematics and when further symbolic calculations are needed, as they offer the utmost precision. When decimal values are necessary, approximation can be used as in \( x \approx 0.231 \), but this represents an approximate solution derived from \( \ln(2) \approx 0.693 \).
- Exact solutions preserve purity and precision
- Utilize symbolic representation wherever possible
- Approximate only when necessary
Other exercises in this chapter
Problem 525
Use logarithms to find the exact solution for \(7 \cdot 17^{-9 x}-7=49 .\) If there is no solution, write no solution.
View solution Problem 526
Use logarithms to find the exact solution for \(3 e^{6 n-2}+1=-60 .\) If there is no solution, write no solution.
View solution Problem 528
Find the exact solution for \(2 e^{5 x-2}-9=-56 .\) If there is no solution, write no solution.
View solution Problem 529
Find the exact solution for \(5^{2 x-3}=7^{x+1} .\) If there is no solution, write no solution.
View solution