Problem 52
Question
Write the point-slope form of the equation of the line that passes through the two points. $$ (-2,3),(2,-5) $$
Step-by-Step Solution
Verified Answer
The equation of the line that passes through the points (-2,3) and (2,-5) is \( y = -2x + 7 \) in point-slope form.
1Step 1: Calculate the Slope
The slope of a line passing through the points \((-2,3)\) and \((2,-5)\) is given by the formula \( m = \frac{{y2 - y1}}{{x2 - x1}} \). Substituting the given points into this formula gives: \(m = \frac{{-5 - 3}}{{2 - (-2)}} = \frac{{-8}}{{4}} = -2 \). So, the slope of the line is -2.
2Step 2: Substitute into the Point-Slope Formula
The point-slope form of a line is given by \( y - y1 = m(x - x1) \). Substituting the slope -2 found in Step 1, and one of the points, say (-2,3), into this formula gives: \( y - 3 = -2(x - (-2)) \). Simplifying this gives \( y - 3 = -2x - 4 \).
3Step 3: Rewrite in Standard Form
The equation \( y - 3 = -2x - 4 \) can be rewritten in standard form by first distributing the -2 through the parentheses, which gives \( y - 3 = -2x + 4 \). Then, isolating y in the equation results in \( y = -2x + 7 \).
Key Concepts
Slope CalculationLinear EquationsStandard Form
Slope Calculation
In mathematics, calculating the slope is vital when understanding lines and their relationships on a graph. The slope of a line is essentially a measure of its steepness or incline, indicating how much the line rises or falls as you move from left to right. When provided with two points, such as
By substituting the values into the equation, we find that the slope \( m = \frac{{-5 - 3}}{{2 - (-2)}} = \frac{{-8}}{{4}} = -2 \).
A negative slope, such as \(-2\), indicates the line descends from left to right.
- \((-2, 3)\) and
- \((2, -5)\),
By substituting the values into the equation, we find that the slope \( m = \frac{{-5 - 3}}{{2 - (-2)}} = \frac{{-8}}{{4}} = -2 \).
A negative slope, such as \(-2\), indicates the line descends from left to right.
Linear Equations
Linear equations form the backbone of algebra and are equations that graph as straight lines. These equations are usually represented in various forms, including the point-slope form, slope-intercept form, and standard form.
The point-slope form, given by \( y - y_1 = m(x - x_1) \), is particularly useful when you know a point on the line and the slope.
In our case, substituting the slope \(-2\) and the point
This equation describes our line in terms of its slope and a specific point, giving valuable insights into the line's direction and position.
The point-slope form, given by \( y - y_1 = m(x - x_1) \), is particularly useful when you know a point on the line and the slope.
In our case, substituting the slope \(-2\) and the point
- \((-2, 3)\)
This equation describes our line in terms of its slope and a specific point, giving valuable insights into the line's direction and position.
Standard Form
The standard form of a linear equation is another way to express a line. It is typically written as \( Ax + By = C \), where \(A\), \(B\), and \(C\) are integers, and \(A\) should be non-negative.
Converting an equation from point-slope or slope-intercept form to standard form can make it easier to understand a graph and to see where a line might intersect the axes.
For the equation \( y - 3 = -2(x + 2) \), we simplify and rearrange it to \( y = -2x + 7 \).
To convert this to standard form, we rearrange terms to isolate the variables on one side, resulting in \( 2x + y = 7 \).
Notice how \( A = 2 \), \( B = 1 \), and \( C = 7 \), which helps in seeing the line's characteristics, such as intercept points on the axes.
Converting an equation from point-slope or slope-intercept form to standard form can make it easier to understand a graph and to see where a line might intersect the axes.
For the equation \( y - 3 = -2(x + 2) \), we simplify and rearrange it to \( y = -2x + 7 \).
To convert this to standard form, we rearrange terms to isolate the variables on one side, resulting in \( 2x + y = 7 \).
Notice how \( A = 2 \), \( B = 1 \), and \( C = 7 \), which helps in seeing the line's characteristics, such as intercept points on the axes.
- The x-intercept occurs when \( y = 0 \),
- and the y-intercept occurs when \( x = 0 \).
Other exercises in this chapter
Problem 51
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