Problem 52
Question
Write an equation for each conic. Each parabola has vertex at the origin, and each ellipse or hyperbola is centered at the origin. $$\text { Focus }(0,-2) ; e=\frac{2}{3}$$
Step-by-Step Solution
Verified Answer
The equation of the ellipse is \(\frac{x^2}{5} + \frac{y^2}{9} = 1\).
1Step 1: Identify conic type
The given conic has a focus at \((0, -2)\) and an eccentricity \(e = \frac{2}{3}\). Since \(e < 1\), this indicates that the conic is an ellipse.
2Step 2: Determine the direction of the ellipse
The focus at \((0, -2)\) suggests that the major axis of the ellipse is vertical, as the ordinate (y-coordinate) changes from the center (origin) to the focus.
3Step 3: Use eccentricity to find \\(a\\) and \\(b\\)
The formula for eccentricity of an ellipse is \(e = \frac{c}{a}\), where \(c\) is the distance from the center to the focus, and \(a\) is the semi-major axis. Given \(c = 2\) and \(e = \frac{2}{3}\), we find that \(a = \frac{c}{e} = \frac{2}{\frac{2}{3}} = 3\).
4Step 4: Calculate \\(b\\) using the ellipse relationship
For an ellipse, the relationship between \(a\), \(b\), and \(c\) is \(b^2 = a^2 - c^2\). So we have \(b^2 = 3^2 - 2^2 = 9 - 4 = 5\), giving \(b = \sqrt{5}\).
5Step 5: Write the equation of the ellipse
An ellipse with a vertical major axis and centered at the origin has the equation \(\frac{x^2}{b^2} + \frac{y^2}{a^2} = 1\). Substituting the values of \(a\) and \(b\), the equation becomes \(\frac{x^2}{5} + \frac{y^2}{9} = 1\).
Key Concepts
EllipseEccentricitySemi-major axisEquation of Ellipse
Ellipse
An ellipse is a type of conic section that appears like a stretched circle. It has two focal points, or foci, and any point on the ellipse is such that the sum of the distances to these foci is constant. Ellipses are important in geometry, astronomy, and optics. You might hear them being associated with orbits of planets and satellites.
Key properties of an ellipse include:
Key properties of an ellipse include:
- Major Axis: This is the longest diameter of the ellipse, running through its center and both its foci.
- Minor Axis: Perpendicular to the major axis, it's the shortest diameter.
- Center: The midpoint of both the major and minor axes.
- Vertices: Points where the ellipse intersects the major axis.
Eccentricity
Eccentricity is a measure of how much a conic section deviates from being a circle. For ellipses, this value is always between 0 and 1. A lower eccentricity indicates a shape closer to a circle, while a higher eccentricity suggests a more elongated ellipse.
This value is a ratio given by the formula:
For example, if the eccentricity is \( \frac{2}{3} \), it means that the ellipse is not overly elongated but still has noticeable stretching compared to a circle. Knowing the eccentricity helps you understand the shape and geometry of the ellipse.
This value is a ratio given by the formula:
- \( e = \frac{c}{a} \)
- e: Eccentricity
- c: Distance from the center to a focus
- a: Length of the semi-major axis
For example, if the eccentricity is \( \frac{2}{3} \), it means that the ellipse is not overly elongated but still has noticeable stretching compared to a circle. Knowing the eccentricity helps you understand the shape and geometry of the ellipse.
Semi-major axis
The semi-major axis is half of the longest diameter of the ellipse. It measures from the center of the ellipse to the farthest point on the perimeter along the major axis. This axis is crucial as it helps define the overall size and shape of the ellipse.
In the context of orbits, the semi-major axis can tell us how far an object travels from the center point (like a planet from the sun). In our given problem, the semi-major axis was determined to be 3 units long using the eccentricity and the focus distance.
Calculating the semi-major axis is straightforward using the formula:
In the context of orbits, the semi-major axis can tell us how far an object travels from the center point (like a planet from the sun). In our given problem, the semi-major axis was determined to be 3 units long using the eccentricity and the focus distance.
Calculating the semi-major axis is straightforward using the formula:
- \( a = \frac{c}{e} \)
Equation of Ellipse
The equation of an ellipse depends on the orientation of its major axis and the lengths of its axes. A standard ellipse centered at the origin has either a horizontal or vertical major axis.
For a horizontal major axis:
For example, with \( a = 3 \) and \( b = \sqrt{5} \), and the major axis being vertical, the equation becomes:
For a horizontal major axis:
- \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \)
- \( \frac{x^2}{b^2} + \frac{y^2}{a^2} = 1 \)
For example, with \( a = 3 \) and \( b = \sqrt{5} \), and the major axis being vertical, the equation becomes:
- \( \frac{x^2}{5} + \frac{y^2}{9} = 1 \)
Other exercises in this chapter
Problem 52
Graph each hyberbola by hand. Give the domain and range. Do not use a calculator. $$x^{2}-y^{2}=1$$
View solution Problem 52
Decide whether each equation has a circle as its graph. If it does, give the center and radius. $$x^{2}+4 x+y^{2}-8 y+32=0$$
View solution Problem 53
Graph each hyberbola by hand. Give the domain and range. Do not use a calculator. $$9 x^{2}-4 y^{2}=1$$
View solution Problem 53
Decide whether each equation has a circle as its graph. If it does, give the center and radius. $$x^{2}-2 x+y^{2}+4 y=0$$
View solution