Problem 52
Question
Why are there no intercepts on the graph of \(y=\csc x ?\)
Step-by-Step Solution
Verified Answer
The graph of \( y = \csc x \) has no intercepts because \( y \) can never be zero.
1Step 1: Understand the Cosecant Function
The cosecant function, represented as \( y = \csc x \), is the reciprocal of the sine function. This means it can be written as \( y = \frac{1}{\sin x} \).
2Step 2: Identify Zeroes of Sine
In the cosecant function, \( y \) becomes undefined wherever \( \sin x = 0 \). The zeros of the sine function, \( \sin x = 0 \), occur at \( x = n\pi \) where \( n \) is an integer.
3Step 3: Determine Where \( y \) Can Never Be Zero
To find the intercepts, we would need \( y = 0 \), which implies \( \frac{1}{\sin x} = 0 \). This equation can never be true, because there is no real number that makes a reciprocal equal to zero. Thus, \( y = \csc x \) has no \( x \)-intercepts.
4Step 4: Verify Using Function Restrictions
Since the function \( \csc x \) is undefined where \( \sin x = 0 \), the function has discontinuities at every integer multiple of \( \pi \), further indicating that there are no points where the graph crosses the \( x \)-axis.
Key Concepts
Reciprocal Trigonometric FunctionsSine Function ZerosUndefined FunctionsDiscontinuities in Trigonometric Graphs
Reciprocal Trigonometric Functions
The cosecant function, represented as \( y = \csc x \), is what we call a reciprocal trigonometric function. Simply put, it is the inverse of the sine function. To express it mathematically, we write \( y = \frac{1}{\sin x} \).
This reciprocal relationship implies that the values of the cosecant function flip those of the sine function. Whenever sine reaches a small value, cosecant results in a large value, and vice versa.
This reciprocal relationship implies that the values of the cosecant function flip those of the sine function. Whenever sine reaches a small value, cosecant results in a large value, and vice versa.
- Understanding the reciprocal nature helps in visualizing how these functions behave differently on a graph.
- It also indicates when and why the cosecant function becomes undefined or has a certain path on a graph.
Sine Function Zeros
In trigonometry, zeros of a function are values of \( x \) for which the function equals zero. For the sine function, this means looking at those \( x \) values where \( \sin x = 0 \).
Interestingly, these zeros occur at very regular intervals. Specifically, \( \sin x = 0 \) when \( x = n\pi \), where \( n \) is any integer.
Interestingly, these zeros occur at very regular intervals. Specifically, \( \sin x = 0 \) when \( x = n\pi \), where \( n \) is any integer.
- This means every multiple of \( \pi \) (e.g., \( 0, \pi, 2\pi, \ldots \)) is where the sine curve crosses the x-axis.
- These points are crucial when considering the behavior of \( y = \csc x \), as they serve as locations where the cosecant function becomes undefined.
Undefined Functions
An undefined function is one that doesn't exist for certain input values. In the case of \( y = \csc x \), it's undefined wherever the sine function \( \sin x \) equals zero.
This is because you can't divide a number by zero—\( \frac{1}{0} \) is not a number. It results in the function being undefined at those points.
This is because you can't divide a number by zero—\( \frac{1}{0} \) is not a number. It results in the function being undefined at those points.
- For \( \csc x \), this happens at \( x = n\pi \).
- Understanding where a function becomes undefined aids in graphing, because you know there will be gaps, or vertical asymptotes.
Discontinuities in Trigonometric Graphs
Discontinuities in a graph appear when there are breaks or jumps. For \( y = \csc x \), these occur at the zeros of the sine function—whenever \( x = n\pi \).
These breaks happen because the function becomes undefined at these points, preventing the graph from having continuous values.
These breaks happen because the function becomes undefined at these points, preventing the graph from having continuous values.
- The result is a series of vertical asymptotes, creating a zigzag pattern on either side of these lines.
- This is why, when graphed, the cosecant function appears with multiple segments that never join smoothly.
Other exercises in this chapter
Problem 49
Explain how the graph of the sine function can be used to graph \(y=\csc x\)
View solution Problem 51
Explain why the period of \(\tan x\) is equal to \(\pi\)
View solution Problem 53
How does the period of \(y=\csc x\) compare with the period of \(y=\sin x ?\)
View solution Problem 58
For the following exercises, find the period and horizontal shift of each of the functions. $$ f(x)=2 \tan (4 x-32) $$
View solution