Problem 52
Question
Which of the following is not correct? (a) ozone is used to identify the presence of unsaturation in alkenes (b) sodium thiosulphate reacts with iodine to form sodium suphate (c) iodine oxidizes sodium thiosulphate to sodium tetrathionate (d) sodium thiosulphate is soluble in water
Step-by-Step Solution
Verified Answer
Option (b) is not correct.
1Step 1: Understanding Each Option
Read each option carefully.
- (a) Ozone is used in ozonolysis, where it reacts with alkenes to identify unsaturation by breaking double bonds. This statement is correct.
- (b) Sodium thiosulphate does not react with iodine to form sodium sulphate; it forms sodium tetrathionate and sodium iodide. This statement is incorrect.
- (c) Iodine oxidizes sodium thiosulphate to sodium tetrathionate, indeed forming sodium tetrathionate and sodium iodide, so this statement is correct.
- (d) Sodium thiosulphate is soluble in water, making this statement correct as well.
2Step 2: Identifying the Incorrect Statement
Based on the evaluations from Step 1, the incorrect option is (b) because the reaction between sodium thiosulphate and iodine produces sodium tetrathionate, not sodium sulphate.
Key Concepts
Chemical ReactionsOzonolysisOxidationSolubility
Chemical Reactions
Chemical reactions occur when substances transform into new substances with different properties. It’s the foundation of chemistry. Reactions involve breaking and forming bonds between atoms. This process requires an understanding of reactants, products, and the conditions under which reactions occur.
In this particular reaction, iodine oxidizes sodium thiosulphate to produce sodium tetrathionate and sodium iodide, illustrating both the transformation of substances and the re-arrangement of atoms that characterize chemical reactions.
- Reactants: The starting materials in a chemical reaction.
- Products: The substances formed as a result of the reaction.
In this particular reaction, iodine oxidizes sodium thiosulphate to produce sodium tetrathionate and sodium iodide, illustrating both the transformation of substances and the re-arrangement of atoms that characterize chemical reactions.
Ozonolysis
Ozonolysis is a specific type of chemical reaction used to study unsaturation in organic compounds. It is a highly effective method for cleaving double bonds in alkenes. When ozone is bubbled through a solution containing alkenes, it reacts with the double bonds according to the following pathway: the alkene undergoes ozonolysis to split into smaller molecules.
Why is Ozonolysis Important?
Why is Ozonolysis Important?
- Identifies the presence of unsaturation by cleaving carbon-carbon double bonds.
- The reaction provides structural insights by revealing the products formed after the cleavage.
Oxidation
Oxidation is a key concept in both chemistry and everyday life. It involves the loss of electrons from a molecule, atom, or ion. This process is often associated with gaining oxygen or losing hydrogen. In the realm of chemical reactions, oxidation is crucial for forming new compounds.
Understanding Oxidation Reactions
In the case of sodium thiosulphate reacting with iodine, iodine acts as an oxidizing agent. It accepts electrons from sodium thiosulphate, undergoing a reduction itself while oxidizing sodium thiosulphate to form sodium tetrathionate.
Understanding Oxidation Reactions
In the case of sodium thiosulphate reacting with iodine, iodine acts as an oxidizing agent. It accepts electrons from sodium thiosulphate, undergoing a reduction itself while oxidizing sodium thiosulphate to form sodium tetrathionate.
- This demonstrates the principle of redox reactions, where oxidation and reduction occur simultaneously.
Solubility
Solubility refers to a substance's ability to dissolve in a solvent, like water. It’s an essential property that influences how substances mix and react with each other.
Key Aspects of Solubility
Key Aspects of Solubility
- Saturability: How much solute can dissolve until a solution becomes saturated.
- Temperature: Generally, solubility of solids in liquids increases with temperature.
- Nature of the solute and solvent: "Like dissolves like"—polar solutes dissolve in polar solvents, while non-polar solutes dissolve in non-polar solvents.
Other exercises in this chapter
Problem 50
The gas \(\mathrm{O}_{3}\) (ozone) cannot oxidize (a) \(\mathrm{KI}\) (b) \(\mathrm{FeSO}_{4}\) (c) \(\mathrm{KMnO}_{4}\) (d) \(\mathrm{K}_{2} \mathrm{MnO}_{4}\
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Which one of the following pairs of reactant does not form oxygen when they react with each other? (a) \(\mathrm{Cl}_{2}, \mathrm{NaOH}\) solution (cold, dilute
View solution Problem 53
Nitrogen is a relatively inactive element because (a) dissociation energy of its molecule is fairly high (b) its electronegativity is fairly high (c) it has low
View solution Problem 54
Which of the following statements is not correct for nitrogen? (a) its molecular size is small (b) it is a typical non-metal (c) d orbitals are available for bo
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