Problem 52
Question
When an elementary function \(f\) is approximated by a second-degree polynomial \(P_{2}\) centered at \(c,\) what is known about \(f\) and \(P_{2}\) at \(c ?\) Explain your reasoning.
Step-by-Step Solution
Verified Answer
The function \(f\) and the second-degree Taylor polynomial \(P_2\), centered at \(c\), are equal at \(c\) (i.e., \(f(c) = P_2(c)\)). This is because the other terms in the polynomial \(P_2\) go to zero at \(x = c\), leaving only the \(f(c)\) term.
1Step 1: Understand Concept of Taylor Series
The Taylor series of a real or complex-valued function \(f(x)\) that is infinitely differentiable at a real or complex number \(a\) is the power series: \(f(a) + f'(a)(x-a) + \frac{f''(a)(x-a)^2}{2!} + \frac{f'''(a)(x-a)^3}{3!} + \ldots \)where \(f'(a)\) denotes the derivative of \(f\) at \(a\), \(f''(a)\) denotes the second derivative of \(f\) at \(a\), and so on.
2Step 2: Analyzing the Specifics of the Problem
In the given problem, we're dealing with a second degree Taylor Polynomial, \(P_2\), centered at \(c\). This can be specifically expressed as:\(P_2(x) = f(c) + f'(c)(x-c) + \frac{f''(c)(x-c)^2}{2!}\)So, we can see that \(P_2(c) = f(c) + f'(c)(c-c) + \frac{f''(c)(c-c)^2}{2!} = f(c)\) because the other terms go to zero because of the \(x-c\) factor. Therefore, the function \(f\) and the Taylor polynomial \(P_2\) are both equal at \(x=c\).
3Step 3: Inference
Thus we see that when the function \(f\) is approximated by a second-degree Taylor polynomial \(P_2\), centered at \(c\), both \(f\) and \(P_2\) have the same value at \(c\) (namely, \(f(c) = P_2(c)\)). This is a fundamental property of Taylor series and provides a notion of the best approximation of the function near point \(c\).
Key Concepts
Taylor PolynomialSecond-degree PolynomialFunction ApproximationElementary Function
Taylor Polynomial
A Taylor Polynomial is a crucial tool in calculus and mathematical analysis that allows us to approximate more complex functions with simpler polynomial expressions. This approximation is based on the function's values and its derivatives at a single point, known as the center of the polynomial. The Taylor polynomial of order \(n\) for a function \(f\) at a point \(a\) is expressed in the form:
- \(P_n(x) = f(a) + f'(a)(x-a) + \frac{f''(a)(x-a)^2}{2!} + \ldots + \frac{f^{(n)}(a)(x-a)^n}{n!}\)
Second-degree Polynomial
A second-degree polynomial, also known as a quadratic polynomial, is a polynomial of the form \(ax^2 + bx + c\). In the context of Taylor series, the second-degree polynomial focuses on approximating a function using terms up to \(x^2\). Specifically, for a function \(f\) centered at \(c\), the second-degree Taylor polynomial is written as:
- \(P_2(x) = f(c) + f'(c)(x-c) + \frac{f''(c)(x-c)^2}{2!} \)
Function Approximation
Function approximation is the process of finding simpler functions that can closely represent more complex functions. In mathematics, this is commonly done using a Taylor Series or Taylor Polynomial. These approximations are particularly useful when exact values are difficult to compute, or to analyze functions in a specific region or interval.
- Taylor Polynomials can approximate functions to varying degrees of accuracy, depending on the degree of the polynomial used.
- For example, a second-degree polynomial approximation provides a simpler form that matches the function's value, slope, and curvature at the center.
Elementary Function
An elementary function is a function composed of basic functions such as polynomials, exponentials, logarithms, and trigonometric functions. These functions are ubiquitous in mathematical practices due to their straightforward behavior and broad applicative scope. Approximating an elementary function using a Taylor polynomial involves evaluating its values and derivatives at a particular point.
- For instance, when approximating \(\sin(x)\) around zero using a second-degree Taylor polynomial, the result smooths into a simple polynomial \(x - \frac{x^3}{6}\).
Other exercises in this chapter
Problem 52
In Exercises 49-54, show that the function represented by the power series is a solution of the differential equation. $$ y=\sum_{n=0}^{\infty} \frac{x^{2 n}}{(
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Use the Limit Comparison Test to determine the convergence or divergence of the series. $$ \sum_{n=1}^{\infty} \frac{2}{3^{n}-5} $$
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Use a power series to approximate the value of the integral with an error of less than \(0.0001 .\) (In Exercises 51 and \(52,\) assume that the integrand is de
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Use the Ratio Test to determine the convergence or divergence of the series. $$ \sum_{n=1}^{\infty} \frac{n^{n}}{n !} $$
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