Problem 52
Question
Use similar triangles to find the coordinates of the point \(Q\) that divides the segment from \(P_{1}\left(x_{1}, y_{1}, z_{1}\right)\) to \(P_{2}\left(x_{2}, y_{2}, z_{2}\right)\) into two lengths whose ratio is \(p / q=r\).
Step-by-Step Solution
Verified Answer
The coordinates of point \( Q \) are \( \left(\frac{px_2 + qx_1}{p+q}, \frac{py_2 + qy_1}{p+q}, \frac{pz_2 + qz_1}{p+q}\right) \).
1Step 1: Understand the problem
We need to find the coordinates of a point \( Q \) on the line segment joining points \( P_1(x_1, y_1, z_1) \) and \( P_2(x_2, y_2, z_2) \), such that the ratio of the lengths of \( P_1Q \) to \( QP_2 \) is \( \frac{p}{q} = r \). This is a problem involving similar triangles and the section formula.
2Step 2: Apply section formula
The section formula in three dimensions states that a point \( Q(x, y, z) \) that divides a line segment joining points \( P_1(x_1, y_1, z_1) \) and \( P_2(x_2, y_2, z_2) \) in the ratio \( m:n \) has coordinates given by: \( (x, y, z) = \left(\frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n}, \frac{mz_2 + nz_1}{m+n}\right) \).
3Step 3: Substitute into section formula
Substitute \( m = p \) and \( n = q \) into the section formula. The coordinates of point \( Q \) are: \( \left(\frac{px_2 + qx_1}{p+q}, \frac{py_2 + qy_1}{p+q}, \frac{pz_2 + qz_1}{p+q}\right) \).
4Step 4: Verify the ratio condition
By substituting the coordinates of \( Q \) back into the section formula, verify that \( Q \) divides the line segment from \( P_1 \) to \( P_2 \) in the ratio \( \frac{p}{q} \). This can be checked by examining the linearity of the coordinates.
Key Concepts
Section FormulaCoordinate GeometryRatios and Proportions
Section Formula
The section formula is an invaluable tool in coordinate geometry which allows us to find a point on a line segment divided in a specific ratio. Imagine you have two points, say \( P_1(x_1, y_1, z_1) \) and \( P_2(x_2, y_2, z_2) \), and you want to find another point, \( Q(x, y, z) \), that divides this segment in a given ratio, \( m:n \). The section formula gives us exactly how to calculate the coordinates of point \( Q \).
- In two-dimensional space, the formula is \( (x, y) = \left(\frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n}\right) \).
- When we bring it to three-dimensional space, it becomes \( (x, y, z) = \left(\frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n}, \frac{mz_2 + nz_1}{m+n}\right) \).
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, combines algebra and geometry to solve spatial problems with points, lines, and shapes. By assigning coordinates, we can use equations and algebraic techniques to explore geometric properties.
- Two main components are involved: the coordinate plane and algebraic expressions.
- Each point on the plane is defined by a set of numbers representing its position along the X, Y, and possibly Z-axes for three-dimensional problems.
Ratios and Proportions
Ratios and proportions are fundamental concepts in mathematics, offering a way to compare quantities. A ratio is simply a way to show how two numbers relate to each other by division, whereas a proportion implies that two ratios are equal.
- Ratios are expressed as \( a:b \) or \( \frac{a}{b} \).
- Proportions are equations that state that two ratios are equivalent, such as \( \frac{a}{b} = \frac{c}{d} \).
Other exercises in this chapter
Problem 51
Find the center \(C\) and the radius \(a\) for the spheres. $$(x+2)^{2}+y^{2}+(z-2)^{2}=8$$
View solution Problem 52
Plot the surfaces in Exercises over the indicated domains. If you can, rotate the surface into different viewing positions. \(z=x^{2}+2 y^{2} \quad\) over a. \(
View solution Problem 52
Find the acute angles between the lines and planes. $$x=2, y=3+2 t, z=1-2 t ; \quad x-y+z=0$$
View solution Problem 52
Find the center \(C\) and the radius \(a\) for the spheres. $$(x-1)^{2}+\left(y+\frac{1}{2}\right)^{2}+(z+3)^{2}=25$$
View solution