Problem 52
Question
The following result is known as Vandermonde's identity, after the German mathematician Abnit-Theophile Vandermonde \((1735-1796) :\) $$ \left(\begin{array}{c}{m+n} \\\ {r}\end{array}\right)=\left(\begin{array}{c}{m} \\\ {0}\end{array}\right)\left(\begin{array}{c}{n} \\\ {r}\end{array}\right)+\left(\begin{array}{c}{m} \\\ {1}\end{array}\right)\left(\begin{array}{c}{n} \\\ {1}\end{array}\right)\left(\begin{array}{c}{n} \\\ {r-1}\end{array}\right)+\left(\begin{array}{c}{m} \\\ {2}\end{array}\right)\left(\begin{array}{c}{n} \\\ {r-2}\end{array}\right)+\cdots+\left(\begin{array}{c}{m} \\\ {r}\end{array}\right)\left(\begin{array}{c}{n} \\ {0}\end{array}\right) $$ Using Exercises \(48-51,\) predict a formula for \(\sum_{i=1}^{n}\left(\begin{array}{l}{i} \\ {k}\end{array}\right)\)
Step-by-Step Solution
VerifiedKey Concepts
Binomial Coefficients
- \(\binom{n}{k} = \frac{n!}{k!(n-k)!}\)