Problem 52
Question
The following problems all involve the concept of borrowing. Subtract in case. \(7 \frac{1}{6}-6 \frac{5}{6}\)
Step-by-Step Solution
Verified Answer
The result is \(\frac{1}{3}\).
1Step 1: Understand the Problem
We have the expression \(7 \frac{1}{6} - 6 \frac{5}{6}\). This means we need to subtract one mixed number from another. In this context, borrowing might be necessary because the fraction \(\frac{1}{6}\) is smaller than \(\frac{5}{6}\).
2Step 2: Borrowing from the Whole Number
Since the fraction \(\frac{1}{6}\) in \(7 \frac{1}{6}\) is less than \(\frac{5}{6}\), we need to borrow 1 from the whole number 7. This makes the whole number 6 and adds \(\frac{6}{6}\) to the fraction part resulting in \(6 \frac{7}{6}\).
3Step 3: Perform the Subtraction
Now subtract \(6 \frac{5}{6}\) from \(6 \frac{7}{6}\). Subtract the whole numbers: \(6 - 6 = 0\) and the fractions: \(\frac{7}{6} - \frac{5}{6} = \frac{2}{6}\), which simplifies to \(\frac{1}{3}\).
4Step 4: Simplify the Fraction
Simplify \(\frac{2}{6}\) by dividing the numerator and the denominator by their greatest common divisor, which is 2. This simplifies the fraction to \(\frac{1}{3}\). Thus, the answer to the subtraction is \(\frac{1}{3}\).
Key Concepts
Borrowing in SubtractionSimplifying FractionsMixed Numbers
Borrowing in Subtraction
When subtracting mixed numbers, borrowing can become necessary, especially when the fractional part of the first number is smaller than the fractional part of the second.
This is similar to borrowing in basic arithmetic when subtracting whole numbers. In our example, with the expression \(7 \frac{1}{6} - 6 \frac{5}{6}\), we notice \(\frac{1}{6}\) is smaller than \(\frac{5}{6}\).
To solve this, we "borrow" 1 from the whole number 7. This borrowing transforms 7 into 6 and adds an extra "whole" to the fraction.
This is similar to borrowing in basic arithmetic when subtracting whole numbers. In our example, with the expression \(7 \frac{1}{6} - 6 \frac{5}{6}\), we notice \(\frac{1}{6}\) is smaller than \(\frac{5}{6}\).
To solve this, we "borrow" 1 from the whole number 7. This borrowing transforms 7 into 6 and adds an extra "whole" to the fraction.
- The new fraction becomes \(\frac{7}{6}\) because \(1 = \frac{6}{6}\), and we already had \(\frac{1}{6}\).
- Now, the expression looks like \(6 \frac{7}{6} - 6 \frac{5}{6}\).
- By borrowing in this way, the fraction is "fixed" so that subtraction can proceed smoothly.
Simplifying Fractions
Simplifying fractions is essential in ensuring your final answer is in its most reduced form. This step comes especially handy after subtracting, as in our previous result from the expression \(6 \frac{7}{6} - 6 \frac{5}{6}\).
After borrowing and subtracting we ended up with \(\frac{2}{6}\). We simplify fractions by dividing both the numerator and the denominator by their greatest common divisor (GCD).
After borrowing and subtracting we ended up with \(\frac{2}{6}\). We simplify fractions by dividing both the numerator and the denominator by their greatest common divisor (GCD).
- First, identify the GCD. For 2 and 6, the GCD is 2.
- Thus, divide both the numerator and the denominator by 2.
- The simplified fraction becomes \(\frac{1}{3}\).
Mixed Numbers
Mixed numbers are numbers involving both a whole number and a fraction. They are frequently used in everyday life to represent quantities that are not whole.
An example of a mixed number is \(7 \frac{1}{6}\). Here, 7 is the whole number, and \(\frac{1}{6}\) is the fractional part. In mathematical operations such as subtraction, it is crucial to manage both parts correctly.
An example of a mixed number is \(7 \frac{1}{6}\). Here, 7 is the whole number, and \(\frac{1}{6}\) is the fractional part. In mathematical operations such as subtraction, it is crucial to manage both parts correctly.
- Adding and subtracting mixed numbers involves handling both the whole and fractional parts.
- Sometimes, like in our problem, the fraction part isn't large enough to simply "subtract" another fraction from it, requiring strategies like borrowing.
Other exercises in this chapter
Problem 51
Simplify each expression as much as possible. Show that multiplying 3 by 5 is the same as dividing 3 by \(\frac{1}{5}\)
View solution Problem 51
Simplify by dividing the numerator by the denominator. $$\frac{37}{1}$$
View solution Problem 52
Simplify each of the following complex fractions. [Examples 5–7] $$\frac{3 \frac{4}{5}-1 \frac{9}{10}}{6 \frac{5}{6}-2 \frac{3}{4}}$$
View solution Problem 52
Expand and simplify each of the following. $$\left(\frac{3}{8}\right)^{2}\left(\frac{4}{3}\right)^{2}$$
View solution