Problem 52
Question
Solve each equation for \(x\). $$4 a-a x=3 b+b x$$
Step-by-Step Solution
Verified Answer
x = \frac{4a - 3b}{b + a}
1Step 1: Distribute coefficients
Distribute the coefficients on both sides of the equation. The equation is: \[4a - ax = 3b + bx\]No distribution needed here as the terms are already simplified.
2Step 2: Move all terms involving x to one side
To isolate terms with x on one side, add ax on the left and subtract bx on the right:\[4a = 3b + bx + ax\]
3Step 3: Factor x out of the equation
Factor x out from the terms on the right side:\[4a = 3b + x(b + a)\]
4Step 4: Isolate x
Divide both sides of the equation by (b + a) to solve for x:\[x = \frac{4a - 3b}{b + a}\]
Key Concepts
Distributing CoefficientsIsolating VariablesFactoringBalancing Equations
Distributing Coefficients
In this step, we distribute coefficients to simplify the equation. Distributing means multiplying the coefficient outside the parentheses with each term inside. For example, in the equation \(4(a - x) = 4a - 4x\), the 4 is distributed to both 'a' and 'x'.
However, in our exercise, the terms are already simple: \(4a - ax = 3b + bx\). So, no distribution needed, and we can move to the next step.
However, in our exercise, the terms are already simple: \(4a - ax = 3b + bx\). So, no distribution needed, and we can move to the next step.
Isolating Variables
Isolating a variable means getting all instances of it on one side of the equation. This helps us solve for that variable. In our problem, we first rearrange the terms:
\(4a - ax = 3b + bx\), we move all x terms to one side.
We do this through addition or subtraction. Here, we'll add \(ax\) to both sides:
\(4a = 3b + bx + ax\).
This puts all x terms on the right side, helping us get closer to isolating x.
\(4a - ax = 3b + bx\), we move all x terms to one side.
We do this through addition or subtraction. Here, we'll add \(ax\) to both sides:
\(4a = 3b + bx + ax\).
This puts all x terms on the right side, helping us get closer to isolating x.
Factoring
Factoring is used to simplify expressions by taking out the common factor. In the context of solving equations, this step helps isolate the variable we are solving for. For example, in the equation \(4a = 3b + bx + ax\), we see that both terms on the right side contain an 'x'.
We can factor out 'x' to make it easier to isolate. This gives us:
\(4a = 3b + x(b + a)\).
Now, we have x out of the parentheses, making it simpler to solve.
We can factor out 'x' to make it easier to isolate. This gives us:
\(4a = 3b + x(b + a)\).
Now, we have x out of the parentheses, making it simpler to solve.
Balancing Equations
Balancing equations is a fundamental part of solving algebra problems. It's all about ensuring that what we do to one side of the equation, we do to the other. This keeps the equation 'balanced'.
For our equation: \(4a = 3b + x(b + a)\), to isolate x, we divide both sides by (b + a) to keep the equation balanced:
\(x = \frac{4a - 3b}{b + a}\).
This final step solves for x and completes the process of balancing the equation.
For our equation: \(4a = 3b + x(b + a)\), to isolate x, we divide both sides by (b + a) to keep the equation balanced:
\(x = \frac{4a - 3b}{b + a}\).
This final step solves for x and completes the process of balancing the equation.
Other exercises in this chapter
Problem 52
Solve each equation or inequality. $$|12-6 x|+3 \geq 9$$
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Find each product. Write the answer in standard form. $$(-2+3 i)(4-2 i)$$
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Solve each quadratic inequality. Write each solution set in interval notation. $$x^{2}+4 x>-1$$
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Solve each equation. $$\sqrt{2 x-5}=2+\sqrt{x-2}$$
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