Problem 52
Question
Solve each equation by factoring or the Quadratic Formula, as appropriate. $$ 5 x^{2}+20=0 $$
Step-by-Step Solution
Verified Answer
The equation has no real solutions; the solutions are complex.
1Step 1: Set the Equation to Standard Form
The given equation is \( 5x^2 + 20 = 0 \). Start by setting the equation to standard quadratic form \( ax^2 + bx + c = 0 \). Here, it is already in standard form, where \( a = 5 \), \( b = 0 \), and \( c = 20 \).
2Step 2: Solve by Quadratic Formula
Since the equation does not factor easily, use the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]Substitute \( a = 5 \), \( b = 0 \), and \( c = 20 \) into the formula:\[ x = \frac{-0 \pm \sqrt{0^2 - 4 \cdot 5 \cdot 20}}{2 \cdot 5} \]
3Step 3: Calculate the Discriminant
Calculate the discriminant, which is \( b^2 - 4ac \):\[ 0^2 - 4 \cdot 5 \cdot 20 = -400 \]Since the discriminant is negative, the equation has no real solutions.
4Step 4: Interpret the Discriminant Result
As the discriminant is negative, the equation has complex solutions. This means the solutions fall into the realm of complex numbers, indicating that there are no x-intercepts on the real number line.
Key Concepts
Quadratic FormulaComplex NumbersDiscriminant
Quadratic Formula
In mathematics, a key tool for finding the solutions to quadratic equations is the quadratic formula. Quadratic equations take the form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants. The quadratic formula provides a way to find the values of the variable \( x \) that satisfy the equation. The formula is as follows:
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
- It can solve any quadratic equation, regardless of whether it can be easily factored.
- The "\( \pm \)" symbol indicates two possible solutions, corresponding to two roots of the equation.
Complex Numbers
Complex numbers extend the idea of numbers beyond the "real" numbers you may already know, like integers, fractions, or decimals. A complex number consists of a real part and an imaginary part, written as \( a + bi \), where \( a \) is the real part and \( bi \) is the imaginary part.
- The imaginary unit \( i \) is defined such that \( i^2 = -1 \).
- To find complex solutions using the quadratic formula, including negative discriminants, means the solution will be in terms of \( i \).
Discriminant
The discriminant of a quadratic equation is a key value found using the formula \( b^2 - 4ac \). Its value provides important information about the nature of the roots of the equation without needing to solve it fully. Here’s what the discriminant tells you:
- If \( b^2 - 4ac > 0 \), there are two distinct real solutions.
- If \( b^2 - 4ac = 0 \), there is exactly one real solution, often called a repeated or double root.
- If \( b^2 - 4ac < 0 \), there are no real solutions. Instead, the solutions will be complex numbers.
Other exercises in this chapter
Problem 51
For each pair of functions \(f(x)\) and \(g(x)\), find a. \(f(g(x))\) b. \(g(f(x))\) and c. \(f(f(x))\) $$ f(x)=\frac{1}{x} ; \quad g(x)=x^{2}+1 $$
View solution Problem 52
Use a calculator to evaluate each expression. Round answers to two decimal places. $$ 5^{3.9} $$
View solution Problem 52
For each pair of functions \(f(x)\) and \(g(x)\), find a. \(f(g(x))\) b. \(g(f(x))\) and c. \(f(f(x))\) $$ f(x)=\sqrt{x} ; g(x)=x^{3}-1 $$
View solution Problem 53
\(53-56 .\) Use a graphing calculator to evaluate each expression. \(\left[(0.1)^{0.1}\right]^{0.1}\)
View solution