Problem 52
Question
Simplify each expression. Write answers using positive exponents. $$ \frac{y^{-3} y^{-4} y^{0}}{\left(2 y^{-2}\right)^{3}} $$
Step-by-Step Solution
Verified Answer
\( \frac{1}{8y} \)
1Step 1: Apply Exponent Rules to the Numerator
In the numerator, we have terms with the same base 'y' that are being multiplied together: \( y^{-3} y^{-4} y^{0} \). Using the rule \( a^m a^n = a^{m+n} \), we combine the exponents: \( y^{-3-4+0} = y^{-7} \).
2Step 2: Expand the Denominator by Applying Power Rule
In the denominator, \( \left(2y^{-2}\right)^3 \) means we need to apply the power rule, which is \( (ab)^n = a^n b^n \). Thus we have \( 2^3 (y^{-2})^3 = 8 y^{-6} \).
3Step 3: Simplify the Complete Expression
We now have \( \frac{y^{-7}}{8y^{-6}} \). Using the formula \( \frac{a^m}{a^n} = a^{m-n} \), this becomes \( \frac{y^{-7}}{y^{-6}} = y^{-7 - (-6)} = y^{-1} \).
4Step 4: Finalize the Expression
Now substitute back into the expression we handled above: \( \frac{y^{-1}}{8} = \frac{1}{8y} \). The numerator was simplified completely and turned into \( y^{-1} = \frac{1}{y} \), resulting in our final expression with positive exponents.
Key Concepts
Negative ExponentsSimplifying ExpressionsPower Rule
Negative Exponents
When working with negative exponents, it's crucial to understand their meaning. A negative exponent indicates the reciprocal of the base raised to the absolute value of the exponent.
For example, if you have an expression like \( y^{-3} \), this is equivalent to \( \frac{1}{y^3} \).
Essentially, it tells you to "flip" the base to the other side of a fraction.
For example, if you have an expression like \( y^{-3} \), this is equivalent to \( \frac{1}{y^3} \).
Essentially, it tells you to "flip" the base to the other side of a fraction.
- Every time you encounter a negative exponent, convert it by flipping the base and changing the sign to positive.
- This process helps in rewriting expressions in a form that's easier to understand and manipulate, especially when multiplying or dividing.
- Always aim to have positive exponents in your final answer to adhere to standard conventions.
Simplifying Expressions
Simplifying expressions is a key component in algebra and involves condensing complex expressions into simpler forms. Here's how you can approach it.
- Look to combine like terms, especially those with the same base such as \(y^{-3} y^{-4} y^{0}\).
- The exponent rules, especially multiplication and division rules, will be your tools.
- Apply the rule \(a^m a^n = a^{m+n}\) to simplify bases with multiple exponents.
- For division, use \(\frac{a^m}{a^n} = a^{m-n}\) to resolve exponents across division bars.
Power Rule
The power rule focuses on simplifying expressions where an exponent is raised to another power.
This is beautifully summarized by \((ab)^n = a^n b^n\), letting us "distribute" the outer exponent to each component inside the parenthesis.
This is beautifully summarized by \((ab)^n = a^n b^n\), letting us "distribute" the outer exponent to each component inside the parenthesis.
- In our context, consider the expression \(\left(2y^{-2}\right)^3\)
- Apply the power rule by making it \(2^3 (y^{-2})^3\), expanding each factor.
- Calculate \(2^3\), which yields 8, and multiply the exponents on the \(y\), giving \(y^{-6}\).
Other exercises in this chapter
Problem 52
Solve each formula for the specified variable. \(P+\frac{a}{V^{2}}=\frac{R T}{V-b}\) for \(b\) (from physics)
View solution Problem 52
Express each variation model in words. In each equation, \(k\) is the constant of variation. $$ \text { 52. } R=\frac{k L}{d^{2}} $$
View solution Problem 52
Perform each division. Divide \(x^{4}+2+4 x^{2}+3 x+2 x^{3}\) by \(x^{2}+2+x\)
View solution Problem 52
Divide, and then simplify, if possible. See Example 6. $$ \frac{24 a^{6}}{b} \div \frac{64 a^{9}}{b^{2}} $$
View solution