Problem 52
Question
Rewrite the equation so that \(y\) is a function of \(x\). $$-3 x+6 y=12$$
Step-by-Step Solution
Verified Answer
The function of \(x\) is \(y = 0.5x + 2\).
1Step 1: Isolate y term
Start with the original equation \(-3x + 6y = 12\). Add \(3x\) to both sides in order to isolate terms with \(y\) on one side. This leaves us with \(6y = 3x + 12\).
2Step 2: Solve for y
Now, divide the entire equation by \(6\) to solve for \(y\). After division, we get \(y = 0.5x + 2\). This is the function of \(x\).
Key Concepts
Function of a VariableIsolating a VariableLinear Equations
Function of a Variable
In mathematics, a function of a variable describes a relationship between two variables, where one variable depends on the other. In the context of algebraic equations, when we express an equation as a function of a variable, it means solving the equation for one variable in terms of another. This allows us to see how changes in one variable affect the other.
For example, when we have an equation like \(y = 0.5x + 2\), it becomes clear that \(y\) is dependent on the value of \(x\).
For example, when we have an equation like \(y = 0.5x + 2\), it becomes clear that \(y\) is dependent on the value of \(x\).
- The function has the general form \(y = f(x)\), where \(f(x)\) represents an expression involving \(x\).
- Understanding the function makes it easy to predict the value of \(y\) for any given \(x\).
Isolating a Variable
Isolating a variable is a fundamental algebraic technique used to express a specific variable by itself on one side of an equation. This process is essential when converting equations into functions, like solving for \(y\) in terms of \(x\) in a linear equation.
To isolate a variable, we perform operations that systematically simplify the equation.
To isolate a variable, we perform operations that systematically simplify the equation.
- Start by moving all terms containing the variable you want to isolate to one side of the equation. This may involve adding or subtracting terms from both sides.
- Next, if the variable is multiplied by a number, divide both sides of the equation by that number to solve for the variable.
Linear Equations
Linear equations are a type of algebraic equation where each term is either a constant or the product of a constant and a single variable. Linear equations can be expressed in the form \(ax + by = c\), where \(a\), \(b\), and \(c\) are real numbers.
These equations are called 'linear' because they graph as straight lines on a coordinate plane.
These equations are called 'linear' because they graph as straight lines on a coordinate plane.
- Linear equations have a constant rate of change, which is represented by the slope. In the function \(y = 0.5x + 2\), the slope is \(0.5\).
- The equation also contains a constant term, which shifts the line up or down on the graph. Here, the constant is \(2\).
Other exercises in this chapter
Problem 52
Determine whether the ordered pair is a solution of the equation. (Lesson 4.2) $$ -4 x-3 y=-8,(-4,2) $$
View solution Problem 52
Determine whether the graphs of the two equations are parallel lines. Explain your answer. $$line\quad a: 2 x-5 y=-3 line\quad b: 5 x+2 y=6$$
View solution Problem 52
Find the least common denominator (LCD) of each pair of fractions. Then rewrite each pair with their LCD. (Skills Review p.762). $$ \frac{7}{18}, \frac{2}{15} $
View solution Problem 52
In Exercises 52 and 53, use the table showing the boiling point of water (in degrees Fahrenheit) for various altitudes (in feet). $$ \begin{array}{|c|c|c|c|c|c|
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