Problem 52
Question
Polar coordinates of a point are given. Find the rectangular coordinates of each point. $$ \left(-6,-\frac{\pi}{4}\right) $$
Step-by-Step Solution
Verified Answer
The rectangular coordinates are \((-3\sqrt{2}, 3\sqrt{2})\).
1Step 1 - Define the given values
Given polar coordinates are \(\r = -6\theta = -\frac{\pi}{4}\). Identify the values: r = -6 and \theta = -\frac{\pi}{4}.
2Step 2 - Use the conversion formulas
To convert from polar to rectangular coordinates, use the formulas \(x = r \cos(\theta})\) and \(y = r\sin(\theta})\).
3Step 3 - Find x coordinate
Substitute the given values into the formula for x: \(x = -6 \cos \left(-\frac{\pi}{4}\right}) = -6 \cdot \frac{\sqrt{2}}{2} = -3\sqrt{2}\).
4Step 4 - Find y coordinate
Substitute the given values into the formula for y: \(y = -6 \sin \left(-\frac{\pi}{4}\right}) = -6 \cdot -\frac{\sqrt{2}}{2} = 3\sqrt{2}\).
5Step 5 - Write the rectangular coordinates
The rectangular coordinates of the given point are \((-3\sqrt{2}, 3\sqrt{2})\).
Key Concepts
Polar CoordinatesRectangular CoordinatesConversion Formulas
Polar Coordinates
Polar coordinates represent a point in a plane using a distance and an angle. They are written as \( (r, \theta) \), where:
- \( r \) is the radial distance from the origin (the center of the coordinate system) to the point.
- \( \theta \) is the angle measured counterclockwise from the positive x-axis to the line connecting the origin to the point.
Rectangular Coordinates
Rectangular coordinates, also known as Cartesian coordinates, represent a point using horizontal and vertical distances from the origin. They are written as (x, y), where:
- \( x \) is the distance from the y-axis.
- \( y \) is the distance from the x-axis.
Conversion Formulas
To convert polar coordinates to rectangular coordinates, you can use the following formulas:
Start with the given polar coordinates \( (-6, -\frac{\pi}{4}) \).
\( x = -6 \cos(-\frac{\pi}{4}) = -6 \cdot \frac{\sqrt{2}}{2} = -3\sqrt{2} \)
For the y-coordinate:
\( y = -6 \sin(-\frac{\pi}{4}) = -6 \cdot -\frac{\sqrt{2}}{2} = 3\sqrt{2} \)
So, the rectangular coordinates for the polar point \( (-6, -\frac{\pi}{4}) \) are \( (-3\sqrt{2}, 3\sqrt{2}) \).
- \( x = r \cos(\theta) \)
- \( y = r \sin(\theta) \)
Start with the given polar coordinates \( (-6, -\frac{\pi}{4}) \).
- The radial distance \( r = -6 \).
- The angle \( \theta = -\frac{\pi}{4} \).
\( x = -6 \cos(-\frac{\pi}{4}) = -6 \cdot \frac{\sqrt{2}}{2} = -3\sqrt{2} \)
For the y-coordinate:
\( y = -6 \sin(-\frac{\pi}{4}) = -6 \cdot -\frac{\sqrt{2}}{2} = 3\sqrt{2} \)
So, the rectangular coordinates for the polar point \( (-6, -\frac{\pi}{4}) \) are \( (-3\sqrt{2}, 3\sqrt{2}) \).
Other exercises in this chapter
Problem 51
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