Problem 52
Question
Multiply. $$ \left(10 x+\frac{2}{7}\right)\left(10 x-\frac{2}{7}\right) $$
Step-by-Step Solution
Verified Answer
The product is \(100x^2 - \frac{4}{49}\).
1Step 1: Identify the expression format
The expression is of the form \((a+b)(a-b)\), which is a difference of squares.
2Step 2: Apply the difference of squares formula
The difference of squares formula states that \((a+b)(a-b) = a^2 - b^2\). In our expression, \(a = 10x\) and \(b = \frac{2}{7}\).
3Step 3: Square the terms
Calculate \(a^2 = (10x)^2 = 100x^2\) and \(b^2 = \left(\frac{2}{7}\right)^2 = \frac{4}{49}\).
4Step 4: Substitute the squared terms into the formula
Replace \(a^2\) and \(b^2\) in the formula: \(100x^2 - \frac{4}{49}\).
5Step 5: Final result
The product of \((10x + \frac{2}{7})(10x - \frac{2}{7})\) simplifies to \(100x^2 - \frac{4}{49}\).
Key Concepts
Multiplication of BinomialsAlgebraic ExpressionsSquared Terms
Multiplication of Binomials
When multiplying binomials, you're working with two algebraic expressions that are added or subtracted from each other. Binomials have the form \((m + n)(m - n)\), where \(m\) and \(n\) are terms that may include numbers, variables, or both.
Understanding this concept is crucial in algebra as it often appears in polynomial expressions and advanced mathematics.
To multiply binomials like these, there are methods you can use:
Understanding this concept is crucial in algebra as it often appears in polynomial expressions and advanced mathematics.
To multiply binomials like these, there are methods you can use:
- FOIL Method: This stands for First, Outer, Inner, Last, representing the order of multiplying terms.
- Using identities: In this context, the formula \((a+b)(a-b) = a^2 - b^2\) directly applies, simplifying the multiplication process significantly.
Algebraic Expressions
Algebraic expressions form the backbone of algebra. They consist of terms, coefficients, and variables arranged in meaningful ways.
In the expression \((10x + \frac{2}{7})(10x - \frac{2}{7})\), we have two binomials.
An algebraic expression can feature:
In the expression \((10x + \frac{2}{7})(10x - \frac{2}{7})\), we have two binomials.
An algebraic expression can feature:
- Variables: Symbols like \(x\), representing unknown quantities.
- Coefficients: Numbers keeping the variable's company, such as \(10\) in \(10x\).
- Constants: Fixed values, like \(\frac{2}{7}\) in our example.
Squared Terms
Squared terms are fundamental in algebra, appearing in various forms of equations and expressions.
When you square a term, you multiply it by itself. For instance, in \( (10x)^2 \), you multiply \(10x\) by \(10x\).
The rules when handling squared terms include:
Thus, computing squared terms accurately is critical for grasping algebraic concepts and solving related problems.
When you square a term, you multiply it by itself. For instance, in \( (10x)^2 \), you multiply \(10x\) by \(10x\).
The rules when handling squared terms include:
- Squaring variables: For any variable \(x\), \(x^2\) denotes \(x\) multiplied by itself.
- Squaring coefficients: Numbers like \(10\) are squared separately from the variable, so \(10^2 = 100\).
- Overall computation: Both results are combined. Therefore, \((10x)^2\) equals \(100x^2\).
Thus, computing squared terms accurately is critical for grasping algebraic concepts and solving related problems.
Other exercises in this chapter
Problem 52
Simplify each expression. Write each result using positive exponents only. $$ \left(\frac{a^{5} b c^{0}}{a^{7} b^{-2}}\right)^{-3} $$
View solution Problem 52
Given the circle below with radius \(5 y\) centimeters, find its area. Do not approximate \(\pi\).
View solution Problem 52
Multiply. \(\left(x^{2}-4\right)^{2}\)
View solution Problem 53
Subtract \(\left(4 y^{2}-6 y-3\right)\) from the sum of \(\left(8 y^{2}+7\right)\) and \((6 y+9)\)
View solution